Answer:
<em>A = 0.05 V</em>
Explanation:
<u>Sinusoidal Functions</u>
A sinusoid or sinusoidal function is a sine or cosine which general equation is

Or also

Where A is the amplitude or maximum value, w is the angular frequency, t is the time and
is the phase shift.
Comparing the given expression with the general formula

We can establish that A=50 mV = 0.05 V

Answer:
5488 Joules
Explanation:
Use the formula for the potential energy:

To solve this problem, we should recall the law of
conservation of energy. That is, the heat lost by the aluminium must be equal
to the heat gained by the cold water. This is expressed in change in enthalpies
therefore:
- ΔH aluminium = ΔH water
where ΔH = m Cp (T2 – T1)
The negative sign simply means heat is lost. Therefore we
calculate for the mass of water (m):
- 0.5 (900) (20 – 200) = m (4186) (20 – 0)
m = 0.9675 kg
Using same mass of water and initial temperature, the final
temperature T of a 1.0 kg aluminium block is:
- 1 (900) (T – 200) = 0.9675 (4186) (T – 0)
- 900 T + 180,000 = 4050 T
4950 T = 180,000
T = 36.36°C
The final temperature of the water and block is 36.36°C
Answer:
Mass and volume.
Explanation:
The equation for density is always mass divided by volume. To determine the density of a fluid, you would need to find its volume and its mass.