Find the pH of a solution whose hydronium concentration is 1.0 x 10-11

What percent of the ocean is euphotic zone

valina [46]

Depth where light intensity falls to one percent<span> of that at the surface, called the euphotic depth</span>

7 0

4 years ago

What is the volume of 0.1 mole of methane (CH4) ? (One mole of any gas occupies 22.4 L under certain conditions of temperature a

Veronika [31]

Answer:

Option A = 2.2 L

Explanation:

Given data:

volume of one mole of gas = 22.4 L

Volume of 0.1 mole of gas at same condition = ?

Solution:

It is known that one mole of gas at STP occupy 22.4 L volume. The standard temperature is 273.15 K and standard pressure is 1 atm.

For 0.1 mole of methane.

0.1/1 × 22.4 = 2.24 L

0.1 mole of methane occupy 2.24 L volume.

8 0

4 years ago

Read 2 more answers

Which salt is formed by the reaction between hydrochloric acid and sodium hydroxide, write with chemical equation. .

stepan [7]

Answer:

salt sodium chloride (NaCl)

8 0

3 years ago

Calculate the cell potential E at 25°C for the reaction 2 Al(s) + 3 Fe2+(aq) → 2 Al3+(aq) + 3 Fe(s) given that [Fe 2+] = 0.020 M

Elodia [21]

Answer:

1.18 V

Explanation:

The given cell is:

$Al(s)/Al^{3+}(0.10M)||Fe^{2+}(0.020M)/Fe(s)$

Half reactions for the given cell follows:

Oxidation half reaction: $Al(s)\rightarrow Al^{3+}(0.10M)+2e^-;E^o_{Al^{3+}/Al}=-1.66V$

Reduction half reaction: $Fe^{2+}(0.020M)+2e^-\rightarrow Fe(s);E^o_{Fe^{2+}/Fe}=-0.45V$

Multiply Oxidation half reaction by 2 and Reduction half reaction by 3

Net reaction: $2Al(s)+3Fe^{2+}(0.020M)\rightarrow 2Al^{3+}(0.10M)+3Fe(s)$

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the $E^o_{cell}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{cathode}-E^o_{anode}$

Putting values in above equation, we get:

$E^o_{cell}=-0.45-(-1.66)=1.21V$

To calculate the EMF of the cell, we use the Nernst equation, which is:

$E_{cell}=E^o_{cell}-\frac{0.059}{n}\log \frac{[Al^{3+}]^2}{[Fe^{2+}]^3}$

where,

$E_{cell}$ = electrode potential of the cell = ?V

$E^o_{cell}$ = standard electrode potential of the cell = +1.21 V

n = number of electrons exchanged = 6

Putting values in above equation, we get:

$E_{cell}=1.21-\frac{0.059}{6}\times \log(\frac{0.10^2}{0.020^3})\\\\E_{cell}=1.18V$

5 0

4 years ago

a compound is found to contain 31.1% sulfur and 68.9% chlorine determine the empirical formula for the sulfur and chlorine sampl

ollegr [7]

Answer:

Empirical formula = S₁Cl₂ = SCl₂

Explanation:

The empirical formula of a compound is the simplest whole number ratio of each type of atom in a compound.

This compound contains 31.1% sulfur and 68.9% chlorine.

That is 100g of the compound contains 31.1 g of sulfur and 68.9 g of chlorine.

Convert the mass of each element to moles using the molar mass from the periodic table.

Moles of Sulfur = $\frac{31.1}{32.065 } \\$

= 0.9699

Moles of Chlorine= $\frac{68.9}{35.453 } \\$

= 1.9434

Divide each mole value by the smallest number of moles calculated.

Units of sulfur = $\frac{0.9699}{0.9699} \\$

= 1

Units of Chlorine = $\frac{1.9434}{0.9699} \\$

= 2

Empirical formula = S₁Cl₂ = SCl₂

8 0

3 years ago

Find the pH of a solution whose hydronium concentration is 1.0 x 10-11​

Find the pH of a solution whose hydronium concentration is 1.0 x 10-11