Answer: 8.12 g NaCl
Explanation: Use Avogadro's number to find the number of m
moles of NaCl:
8.24x10²² molecules NaCl / 1 mole NaCl/ 6.022x10²³ molecules NaCl
= 0.14 mole NaCl
Next convert moles to grams NaCl using its molar mass;
0.14 mole NaCl x 58g NaCl / 1 mole NaCl
= 8.12 g NaCl
Lead is a basic metal and almost 11 isotopes of Lead are reported. The isotopes with greater natural abundance are as follow;
1) ²⁰⁸Pb with abundance 52.4 %
2) ²⁰⁶Pb with abundance 24.1 %
3) ²⁰⁷Pb with abundance 22.1 %
4) ²⁰⁴Pb with abundance 1.4 %
Molar mass of ²⁰⁸Pb:
Molar mass of any element is the total of number of protons, neutrons and electrons.
As, number of protons in Lead are 82 then in ²⁰⁸Pb isotope number of neutrons are...
# of Neutrons = M.mass - # of protons
# of Neutrons = 208 - 82
# of Neutrons = 126
Result:
Molecular Mass of Lead (²⁰⁸Pb) is 208 amu.
# of Protons in ²⁰⁸Pb = 82
# of Neutrons in ²⁰⁸Pb = 126
Answer:
Percentage of oxygen = 30%
Percentage of carbon = 30%
Percentage of hydrogen = 40%
Explanation:
Formula:
Percentage of element = given amount / total amount × 100
Given compound:
C₆H₈O₆
Number of atoms of carbon = 6
Number of atoms of hydrogen = 8
Number of atoms of oxygen = 6
Total number of atoms = 20
Percentage of carbon = 6/20 × 100
Percentage of carbon = 30%
Percentage of Hydrogen = 8/20 × 100
Percentage of Hydrogen = 40%
Percentage of oxygen = 6/20 × 100
Percentage of oxygen = 30%
Using the Michaelis-Menten equation competitive inhibition, the Inhibition constant, Ki of the inhibitor is 53.4 μM.
<h3>What is the Ki for the inhibitor?</h3>
The Ki of an inhibitor is known as the inhibition constant.
The inhibition is a competitive inhibition as the Vmax is unchanged but Km changes.
Using the Michaelis-Menten equation for inhibition:
Making Ki subject of the formula:
where:
- Kma is the apparent Km due to inhibitor
- Km is the Km of the enzyme-catalyzed reaction
- [I] is the concentration of the inhibitor
Solving for Ki:
where
[I] = 26.7 μM
Km = 1.0
Kma = (150% × 1 ) + 1 = 2.5
Ki = 26.7 μM/{(2.5/1) - 1)
Ki = 53.4 μM
Therefore, the Inhibition constant, Ki of the inhibitor is 53.4 μM.
Learn more about enzyme inhibition at: brainly.com/question/13618533
Answer:
In an ionic bonds, the metal loses electrons to become a positively charged cation, In which the nonmetal accepts those electrons to become a negatively charged anion.
Explanation:
