i am pretty sure it would be a chemical change so A
I honestly don’t know sorry
Answer:
This is a coal combustion process and we will assume
Inlet coal amount = 100kg
It means that there are
15kg of H2O, 2kg of Sulphur and 83kg of Carbon
Now to find the mole fraction of SO2(g) in the exhaust?
Molar mass of S = 32kg/kmol
Initial moles n of S = 2/32 = 0.0625kmols
Reaction: S + O₂ = SO₂
That is 1 mole of S reacts with 1 mole of O₂ to give 1 mole of SO₂
Then, it means for 0.0625 kmoles of S, we will have 0.0625 kmole of SO2 coming out of the exhaust
The mole fraction of SO2(g) in the exhaust=0.0625kmols
Explanation:
Answer:
Molar mass = 1.111 × 10⁻⁵ g/mol
Explanation:
Given data:
Mass of polyethylene = 1.36 g
Volume = 100 mL (0.1 L )
Pressure = 1.86 torr (1.86/760 = 0.003 atm)
Temperature = 25 °C = 25 °C + 273.15 = 298.15 K
Molar mass of polyethylene = ?
Solution :
PV =nRT
n = PV/RT
n = 0.003 atm × 0.1 L / 0.0821 atm. L . mol⁻¹ .k⁻¹ × 298.15 k
n = 0.0003 atm. L / 24.5 atm. L . mol⁻¹
n = 1.2245 × 10⁻⁵ mol
Molar mass = mass / number of moles
Molar mass = 1.36g / 1.2245 × 10⁻⁵ mol
Molar mass = 1.111 × 10⁻⁵ g/mol
Answer:
Adult tickets = A (cost $8)
student tickets = S (cost $4)
8(80) + 4(60) = 880
Explanation:
Substitution.
Adult tickets = A (cost $8)
student tickets = S (cost $4)
The drama class sold 20 more adult tickets than student tickets:
A = S + 20 (equation 1)
The class collected $880 from tickets:
8A + 4S = 880 (equation 2)
How many adult tickets were sold?
A = S + 20
8A + 4S = 880
we substitute the first equation into the second:
8(S+20) + 4S = 880
8S + 160 + 4S = 880
12S = 720
S = 60
Next we find the adult tickets by substituting back:
A = S + 20
A = 60 + 20
A = 80
Check our answer by substituting our answers in equation 2:
8A + 4S = 880 (equation 2)
8(80) + 4(60) = 880
640 + 240 = 880
880 = 880
