I looked up what is the molecular formula for Phosphine and got this: PH3
Hope this helps! Let my know if this was correct.
Answer:
Final molarity of iodide ion C(I-) = 0.0143M
Explanation:
n = (m(FeI(2)))/(M(FeI(2))
Molar mass of FeI(3) = 55.85+(127 x 2) = 309.85g/mol
So n = 0.981/309.85 = 0.0031 mol
V(solution) = 150mL = 0.15L
C(AgNO3) = 35mM = 0.035M = 0.035m/L
n(AgNO3) = C(AgNO3) x V(solution)
= 0.035 x 0.15 = 0.00525 mol
(AgNO3) + FeI(3) = AgI(3) + FeNO3
So, n(FeI(3)) excess = 0.00525 - 0.0031 = 0.00215mol
C(I-) = C(FeI(3)) = [n(FeI(3)) excess]/ [V(solution)] = 0.00215/0.15 = 0.0143mol/L or 0.0143M
Answer:
<u>Osmosis </u>is the process that describes water moving through a membrane.
I am not sure about the second question.
Explanation:
Answer:
24m/s
Explanation:
a=change of v/change of t
6m/s^2=v/4s
multiply both sides by 4s
v=24m/s
Q1. TI (210/81Thallium)
Q2.
The answers are opposite from each other
