<u>Answer:</u> The pH of the buffer is 5.25
<u>Explanation:</u>
Let the volume of buffer solution be V
We know that:

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:
![pH=pK_a+\log(\frac{[\text{conjugate base}]}{[acid]})](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%28%5Cfrac%7B%5B%5Ctext%7Bconjugate%20base%7D%5D%7D%7B%5Bacid%5D%7D%29)
We are given:
= negative logarithm of acid dissociation constant of weak acid = 4.90
![[\text{conjugate base}]=\frac{2.25}{V}](https://tex.z-dn.net/?f=%5B%5Ctext%7Bconjugate%20base%7D%5D%3D%5Cfrac%7B2.25%7D%7BV%7D)
![[acid]=\frac{1.00}{V}](https://tex.z-dn.net/?f=%5Bacid%5D%3D%5Cfrac%7B1.00%7D%7BV%7D)
pH = ?
Putting values in above equation, we get:

Hence, the pH of the buffer is 5.25
A. BeCl2 sp2
Also when you get the chance, could you mark me brainliest?
The answer is: supersaturated solution.
A supersaturated solution contains more of the dissolved substance than could be dissolved by the solvent under normal circumstances.
A way to dissolve more sugar into a solution is heating a solution.
The more heat is added to a system, the more soluble a substance (in this example sugar) becomes.
The solution will become supersaturated if this solution is suddenly cooled at a rate faster than the rate of precipitation.
Answer:
a ) 1876.14 grams CaBr2
b ) 19.78 grams N2
sorry..i only have time to do the first two :)
Explanation: