Answer:
pH = 3.347
NO₂⁻ + H₃O⁺ → HNO₂
Explanation:
If the buffer is made with 0.417M of HNO₂ and 0.417M of NaNO₂ the pH of the solution is = pKa. <em>A buffer which concentration of weak acid and conjugate base is the same has a pH = pKa</em>
As Ka of the solution is 4.50x10⁻⁴, pKa is -log 4.50x10⁻⁴ = 3.347. Thus,<em> pH = 3.347</em>
<em />
The net ionic equation that occurs when 0.120 mol of HCl is added to 1.00L of the solution is:
<em>NO₂⁻ + H₃O⁺ → HNO₂ + H₂O</em>
<em>The conjugate base (NaNO₂) reacts with strong acid (HCl, source of H₃O⁺) producing weak acid (HNO₂) and water. If a strong base is added, the weak acid reacts producing conjugate base and water.</em>
Strontium Phosphate is made from that thing
Answer:
is the isotopic notation of the atom
Explanation:
The isotope notation is:
<em>Where a is the mass number = Number of protons + Number of neutrons</em>
<em>b is atomic number = Number of protons</em>
The atomic number define the nature of the atom, the element with atomic number = 15 is phosphorus, P:
a = 15 protons + 16 neutrons = 31
b = 15
is the isotopic notation of the atom.
Answer:
15.0 µm
Step-by-step explanation:
Density = mass/volume
D = m/V Multiply each side by V
DV = m Divide each side by D
V = m/D
Data:
m = 1.091 g
D = 7.28 g/cm³
l = 10.0 cm
w = 10.0 cm
Calculation:
<em>(a) Volume of foil
</em>
V = 1.091 g × (1 cm³/7.28 g)
= 0.1499 cm³
(b) <em>Thickness of foil
</em>
The foil is a rectangular solid.
V = lwh Divide each side by lw
h = V/(lw)
= 0.1499/(10 × 10)
= 1.50 × 10⁻³ cm Convert to millimetres
= 0.015 mm Convert to micrometres
= 15.0 µm
The foil is 15.0 µm thick.
