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3 years ago

What is another name for the representative elements?

Chemistry

2 answers:

jeka943 years ago

6 0

Answer:

Group A elements or the main group

Another name for the representative elements are the Group A elements or the main group elements

Explanation:

GaryK [48]3 years ago

5 0

Answer:

Another name for the representative elements are the Group A elements or the main group elements.

Explanation:

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In systemic tissue fluids, the enzyme carbonic anhydrase catalyzes the reaction co2 + h2o → h2co3 (which then can dissociate int

NeTakaya

It is achievable for the same enzyme to catalyze reverse reactions for the reason that the direction of a reversible reaction is determined by the concentrations of reactants and products. In pulmonary circulation, the low CO2 concentration supports the making of CO2 and H2O.

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3 years ago

A mixture of 15.0 g of the anesthetic halothane (C2HBrClF3 197.4 g/mol) and 22.6 g of oxygen gas has a total pressure of 862 tor

AlexFokin [52]

Answer : The partial pressure of $C_2HBrClF_3$ and $O_2$ are, 84 torr and 778 torr respectively.

Explanation : Given,

Mass of $C_2HBrClF_3$ = 15.0 g

Mass of $O_2$ = 22.6 g

Molar mass of $C_2HBrClF_3$ = 197.4 g/mole

Molar mass of $O_2$ = 32 g/mole

First we have to calculate the moles of $C_2HBrClF_3$ and $O_2$ .

$\text{Moles of }C_2HBrClF_3=\frac{\text{Mass of }C_2HBrClF_3}{\text{Molar mass of }C_2HBrClF_3}=\frac{15.0g}{197.4g/mole}=0.0759mole$

and,

$\text{Moles of }O_2=\frac{\text{Mass of }O_2}{\text{Molar mass of }O_2}=\frac{22.6g}{32g/mole}=0.706mole$

Now we have to calculate the mole fraction of $C_2HBrClF_3$ and $O_2$ .

$\text{Mole fraction of }C_2HBrClF_3=\frac{\text{Moles of }C_2HBrClF_3}{\text{Moles of }C_2HBrClF_3+\text{Moles of }O_2}=\frac{0.0759}{0.0759+0.706}=0.0971$

and,

$\text{Mole fraction of }O_2=\frac{\text{Moles of }O_2}{\text{Moles of }C_2HBrClF_3+\text{Moles of }O_2}=\frac{0.706}{0.0759+0.706}=0.903$

Now we have to partial pressure of $C_2HBrClF_3$ and $O_2$ .

According to the Raoult's law,

$p^o=X\times p_T$

where,

$p^o$ = partial pressure of gas

$p_T$ = total pressure of gas

$X$ = mole fraction of gas

$p_{C_2HBrClF_3}=X_{C_2HBrClF_3}\times p_T$

$p_{C_2HBrClF_3}=0.0971\times 862torr=84torr$

and,

$p_{O_2}=X_{O_2}\times p_T$

$p_{O_2}=0.903\times 862torr=778torr$

Therefore, the partial pressure of $C_2HBrClF_3$ and $O_2$ are, 84 torr and 778 torr respectively.

6 0

3 years ago

HELP!!! Which element has 6 energy levels and 8 valence electrons?

Art [367]

Answer:

OXYGEN

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3 years ago

What is the mole fraction of ethanol in a solution of 3.00 moles of ethanol and 5.00 moles of water?

Rus_ich [418]

If theres a mixture of components we can calculate the mole fraction
mole fraction can be calculated as follows
mole fraction of component = $\frac{number of moles of component}{total number of moles of all components }$
number of moles of ethanol - 3.00 mol
total number of moles in mixture - 3.00 + 5.00 = 8.00 mol

mole fraction of ethanol = $\frac{3.00 mol}{8.00 mol }$
mole fraction of ethanol is 0.375

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3 years ago

Describe how thin layer chromatography is used in the isolation and extraction of lipids

BabaBlast [244]

Thin layer chromatography(TLC) works with the principle of separation through adsorption.

It is used in the isolation and extraction of lipids through the following steps:

apply the lipid samples spots in the bottom of the plate.
also apply sample solution to the marked spot
pour the mobile phase into the TLC chamber and use a moist filter paper to cover it. this is done to maintain equal humidity.
then place the plate in the TLC chamber and close it with a lid.
the plate is immersed into the solvent (mobile phase) for its development. this is done, keeping in mind that the sample spot should be above the solvent.
once the sample spots are developed, they are removed and dried.
this is later viewed using the UV light chamber to see the isolation of the lipid sample.

Learn more here:

brainly.com/question/3137660

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3 years ago