Correct Ans:Option A. 0.0100
Solution:We are to find the probability that the class average for 10 selected classes is greater than 90. This involves the utilization of standard normal distribution.
First step will be to convert the given score into z score for given mean, standard deviation and sample size and then use that z score to find the said probability. So converting the value to z score:

So, 90 converted to z score for given data is 2.326. Now using the z-table we are to find the probability of z score to be greater than 2.326. The probability comes out to be 0.01.
Therefore, there is a 0.01 probability of the class average to be greater than 90 for the 10 classes.
Answer:
6
Step-by-step explanation:
Hope that helps
Multiply amount sold by commission rate:
4500 x 0.13 = 585
She made $585 last week.
Multiply amount made in 1 week by 52 weeks ( 1 year = 52 weeks)
585 x 52 = 30,420
She made $30,420 in 2011
Answer:
The procedure for this case is add three, then divide by 5.
Step-by-step explanation:
if y=5x-3
to find the inverse, we exchange x and y then solve for the new y.
x=5y-3 add 3
x+3 = 5y divide by 5
(x+3)/5 = y
or
inverse, y=(x+3)/5
The procedure for this case is add three, then divide by 5.