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Illusion [34]
3 years ago
9

The overall magnification of a compound microscope with an objective lens magnification of 5 and an eye piece magnification of 3

0 will be
Physics
2 answers:
Katen [24]3 years ago
3 0
Ok the answer to this is quite simple all you do is multiply the objective lens magnification times the eye piece magnification. So multiply 30 times 5. 30 x 5 = 150. So your answer is answer choice C. 150 Hope this helped you. :)
Ann [662]3 years ago
3 0

Answer:

M = 150 times

Explanation:

When two or more lens are used to form image then final magnification of the image is given by the product of magnification due to each lens

so here we can say

M = m_1 \times m_2 \times m_3 ...............

so here we know that

m_1 = 5

m_2 = 30

now the total magnification is given as

M = m_1 \times m_2

M = 5 \times 30

M = 150

so total magnification is 150 times

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The surface tension of water was determined in a laboratory by using the drop weight method. 100 drops were released from a bure
Lapatulllka [165]

Answer:

γ = 0.06563 N / m

9.78% difference

Explanation:

Solution:-

- Surface tension is the ability of any fluid to resist any external force which causes a decreases in surface area of the impact area due to inward compressive forces. These compressive forces occur due to cohesive nature of the fluid molecules.

- Mathematically, surface tension ( γ ) is defined as the force felt per unit length by the fluid.

                           γ = F / L

Where,

              F: Force imparted

              L: The length over which force is felt

- We are given the mass ( M ) of ( n = 100 ) water droplets to e 3.78 g. The mass of a single droplet ( m ) can be evaluated as follows:

                         m = M / n

                         m = 3.78 / 100

                        m = 0.0378 g        

- The force ( F ) imparted by a single drop of water from the burette can be determined from the force balance on a single droplet. Assuming the distance over which the drop falls is negligible and resistive forces are negligible. Then the only force acting on the droplet is due to gravity:

                        F = m*g

                        F = 0.0378*9.81*10^-3

                        F = 0.000370818 N      

- The length over which the force is felt can be magnified into a circular area with diameter equal to that of a single droplet ( d ). The circumferential length ( L ) of the droplet would be as follows:

                        L = π*d

                        L = π*( 0.0018 )

                        L = 0.00565 m

- Then the surface tension would be:

                        γ = F / L

                        γ = 0.000370818 / 0.00565

                        γ = 0.06563 N / m

- The tabulated value of water's surface tension is given as follows:

                       γa = 0.07275 N/m

- We will determine the percentage difference between the value evaluated  and tabulated value as follows:

                     p.diff = \frac{gamma_a - gamma}{gamma_a} * 100\\\\p.diff = \frac{0.07275- 0.06563}{0.07275} * 100 \\\\p.diff = 9.78 %

- The %difference between is within the allowable practical limits of 10%. Hence, the evaluated value ( γ = 0.06563 N / m ) can be accepted with 9.78% error.

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3 years ago
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8x5x4 = 160 cm ^3
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2 years ago
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Answer:

i thinc it's False

Explanation:

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Answer: 1.67 x 10^-7N

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1. Ask a question
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