Answer:
Explanation:
I'm not sure you can do this without just a bit more information. I can tell you what the mass of the water is when the rocks are removed. When we know that, we know the volume of the water that was displaced. whether or not this is enough information to determine the volume of the box, I'm not sure.
400 grams raises the box 1 cm.
The density of water = 1 gm / cm^3
400 grams of water = 400 mL or 400 cm^3
The volume of the displaced water = 400 cm^3
The volume a slice from the square prism is B*h
B = 400 cm^2
h = 1 cm
If the base is 400 cm^2 then each side is
s^2 = 400
sqrt(s^2)= sqrt(400)
s = 20
The volume of the box is 20^3 = 8000 cm^3
Answer:
Option A
Explanation:
The Equation represents the displacement of the object which is represented by x

so,
means when time is zero so we replace t with zero in the equation,

now for v which is velocity we need to differentiate the function as the formula for velocity is rate of change of displacement over time so we derivate the equation once and get,

now for
we insert t = 0 and get

now for a which is acceleration the formula of acceleration is rate of change of velocity over time, so we differentiate the the equation of v(velocity) once or the equation of x(displacement) twice so now we get,

so Option A is your answer.
Remember derivative of a constant is always zero because a constant value has no rate of change has its a constant hence the derivative is 0
The sun is bright and when its cold there is no sun
Answer:
d = 2,042 10-3 m
Explanation:
The laser diffracts in the circular slit, so the process equation is
d sin θ= m λ
The first diffraction minimum occurs for m = 1
We can use trigonometry in the mirror
tan θ = Y / L
Where L is the distance from the Moon to Earth
Since the angle is extremely small
tan θ = sin θ / cos θ
Cos θ = 1
tant θ = sin θ = y / L
We replace
d y / L = λ
d = λ L / y
Let's calculate
d = 532 10⁻⁹ 3.84 10⁶/1 10³
d = 2,042 10-3 m
No, you would aim slightly above, because when you throw the spear and it travels through the air it will fall slightly downwards by the time it reaches the fish.