What is the difference between deviation and incidence

Physics

2 answers:

yKpoI14uk [10]3 years ago

3 0

Explanation:

Deviation :  

It means the difference between a expected value of a measurement or an observation vs the actual value.

Incidence :

A straight line, ray of light, etc.., hits a surface at a point.

natka813 [3]3 years ago

3 0

Answer:Deviation means from any written procedure that we have implemented. Deviation can be of two different types : 1.Planned Deviation

2.Unplanned Deviation

Incidence is any event that can affect our product quality or not but that is against the cGMP. Ex:Eating food in production area.

Ex: Spillage of material on floor.

Explanation:

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If an object moving at 12 m/s has a kinetic energy of 72 j what is the mass

EleoNora [17]

Simply, apply the formula $E = \frac{1}{2}mv^{2}$ and insert the values of m = mass, v = velocity and E = Energy.
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5 0

3 years ago

A stone is thrown horizontally with an initial speed of 10 m/s from the edge of a cliff. A stopwatch measures the stone's trajec

olga2289 [7]

Answer:

The height of the cliff is 90.60 meters.

Explanation:

It is given that,

Initial horizontal speed of the stone, u = 10 m/s

Initial vertical speed of the stone, u' = 0 (as there is no motion in vertical direction)

The time taken by the stone from the top of the cliff to the bottom to be 4.3 s, t = 4.3 s

Let h is the height of the cliff. Using the second equation of motion in vertical direction to find it. It is given by :

$h=u't+\dfrac{1}{2}gt^2$

$h=\dfrac{1}{2}gt^2$

$h=\dfrac{1}{2}\times 9.8\times (4.3)^2$

h = 90.60 meters

So, the height of the cliff is 90.60 meters. Hence, this is the required solution.

5 0

3 years ago

A large box slides across a frictionless surface with a velocity of 12 m/s and a mass of 4

denpristay [2]

Answer= 8m/s

Because total Momentum before= total momentum after

Momentum before (p=mu)
p=(4)(12)= 48
p=2(0)=0
So total momentum before=48

Momentum after (p=mu)
Masses combined —2+4=6kg
p=6u

Mb=Ma
48=6u
u=8m/s

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2 years ago

How much force is required to accelerate a 5 kg mass at 20 m/s^2

Studentka2010 [4]

Hello!

$\large\boxed{F = 100N}$