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3 years ago

What happens to the force needed to stretch an elastic object?

Physics

1 answer:

avanturin [10]3 years ago

8 0

Answer:

the force pulls each other cause its just physics

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The hydrocarbon used to manufacture foam plastics is called styrene. Analysis shows composition to be 92.25% C and 7.75% H. Anal

zhannawk [14.2K]

Answer:

molecular formula = $C_{8} H_{8}$

Explanation:

Given data

c = 92.25%

H = 7.75%

molar mass = 104 g/mol

to find out

the empirical and molecular formula for styrene

solution

we know that

styrene 1 g contain = 0.9225 g C and 0.0775 g H

C = 104 × 0.9225 g / 12 g/mol

C = 7.995 mol = approx 8 mol

and

H = 104 × 0.0775 g / 1 g/mol

H = 8.06 mol = approx 8 mol

so we say that 1 mole of styrene have 8 mole of C and H

molecular formula = $C_{8} H_{8}$

8 0

4 years ago

The mirror used in search light is:

dolphi86 [110]

Answer:

Explanation:

6 0

3 years ago

A 3.0 pF capacitor consists of two parallel plates that have surface charge densities of 1.0 nC/mm2 . If the potential between t

Archy [21]

Answer:

$A=81mm^2$

Explanation:

We know that for a capacitor $Q=CV$ , where Q is the charge of one plate, C the capacitance and V the potential between the plates.

We also know that $Q=\sigma A$ , since $\sigma$ is the surface charge density and A the area of the plate (both equal in our case).

Putting all together:

$A=\frac{CV}{\sigma}$

Which for our values is:

$A=\frac{(3\times10^{-12}F)(27\times10^3V)}{1\times10^{-9}C/mm^2}=81mm^2$

Where we notice that the S.I. units combination FV/C must not have units (we can verify it directly from their definitions or we notice that $mm^2$ is enough to describe an area).

8 0

3 years ago

The oscillation of the 2.0-kg mass on a spring is described by x = 3.0 cos (4.0 t) where x is in centimeters and t is in seconds

jeka57 [31]

X is the answer because x can be any thing

7 0

2 years ago

An astronaut's pack weighs 17.5 N when she is on earth, but only 3.24 N when she is on the surface of an asteroid. What is the a

Nimfa-mama [501]

Answer:

a= 1.81 m/s²

Explanation:

Ratio of the weights on both surfaces can be calculated as,

$\frac{W_{a} }{W_{E} }$ = $\frac{ma}{mg}$

Here;

Wa is the weight on the asteroid, $W_{E}$ is weight on earth,

m is mass of pack, a is acceleration due to an asteroid and

g is acceleration due to gravity.

Rearrange above equation for a,

a=g ( $\frac{Wa}{W_{E} }$ )

Substitute 3.24 N for Wa, 17.5 N for $W_{E}$ ,

9.81 m/s² for g in the above equation,

a= 9.81( $\frac{3.24}{17.5}$ )

a= 1.81 m/s²

7 0

4 years ago