What happens to the force needed to stretch an elastic object?

What term describes the resistance that one encounters when moving over another

Anvisha [2.4K]

Friction? For example, like when a car's tires skid on rough concrete.

5 0

3 years ago

When converted to a household measurement, 9 kilograms is approximately equal to a

Evgen [1.6K]

Answer:

D) 19.8 lbs

Explanation:

1kg in household measurement is equal to 35.274 ounces. 35.274*9=317.466 ounces.

1kg is also equal to 2.205 lbs. 9*2.205=19.8416

9 kg is also equal to 9000 grams, but grams are not a part of the household measurement system

a) 9000 grams. b) 9000 ounces. c) 19.8 ounces. d) 19.8 pounds.

This leaves us with 19.8lbs

3 0

3 years ago

What does a magnetic field look like <br>

Lelechka [254]

Answer:Magnetic fields are invisible, at least usually. But scientists from NASA's Space Sciences Laboratory have made them visible as "animated photographs," using sound-controlled CGI and 3D compositing.

Explanation:

5 0

4 years ago

The mass of a star is 1.210×1031 kg and it performs one rotation in 20.30 days. Find its new period (in days) if the diameter su

balandron [24]

The new period will be 2.486 days.

<h3>What is the period?</h3>

The period is found as the ratio of the angular displacement and the angular velocity. Its unit is the second and is denoted by t. The value of time needed to complete the rotation is the total period.

Given data;

Mass of a star,m= 1.210×10³¹ kg

The time period for one rotation of the star, T = 20.30 days

D' = 0.350 D

R' = 0.350 R

From the law of conservation of angular momentum;

$\rm I \omega = I' \omega' \\\\ \frac{2}{5} MR^2 \times \frac{2 \pi }{T}=\frac{2}{5} MR'^2 \\\\ R^2 \times \frac{1}{T}= R'^2 \times \frac{1}{T} \\\\ T' = \frac{R'^2T}{R^2} \\\\ T' = \frac{(0.350 R)^2 \times 26.1 }{R^2} \\\\T' = 0.1225 \times 20.30 \\\\ T'= 2.486 \ days$

Hence, the new period will be 2.486 days.

To learn more about the period, refer to the link;

brainly.com/question/569003

#SPJ1

8 0

2 years ago

Infrared radiation has frequencies from 3.0×1011 to 3.0×1014 Hz, whereas the frequency region for microwave radiation is 3.0×108

igor_vitrenko [27]

Answer:

1. The speed of infrared radiation is the same as microwave radiation.

2. The wavelength of infrared radiation is lower than microwave radiation.

Explanation:

1. The speed of infrared radiation is the same as microwave radiation. This is because both infrared radiation and microwave radiation are electromagnetic waves and all electromagnetic waves move at the same speed, the speed of light.

2. Frequency and wavelength has an inverse relationship. This means that the higher the frequency, the lower the wavelength.

Since the frequency range of infrared waves is higher than that of microwaves, the wavelength range of infrared waves is lower than that of microwaves.

We can prove this by using the maximum frequency value of each wave to calculate their corresponding wavelengths.

Speed of light, c, is given as:

c = λf

Where λ is wavelength and f is frequency.

Wavelength is therefore:

λ = c/f

For infrared wave, the maximum frequency is 3 * 10^14 Hz, hence the corresponding wavelength is:

λ = (3 * 10^8) / (3 * 10^14)

λ = 10^(-6) m

For microwave, the maximum frequency is 3 * 10^11 Hz, hence the corresponding wavelength is:

λ = (3 * 10^8) / (3 * 10^11)

λ = 10^(-3) m

Hence, the wavelength of infrared waves is lower than the wavelength of microwaves.

8 0

3 years ago