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Vanyuwa [196]
3 years ago
15

If wave A has a frequency of 4.60 x 10^14 s-1, what is the wavelength in nanometers (show your work)?

Chemistry
1 answer:
victus00 [196]3 years ago
8 0

Answer:

652.174nm

Explanation:

We need to know that the speed of light never changes. It has a value of 3 × 10^8 m/s.

Given only the frequency, we can find the wavelength by dividing the value of the speed of light by the value of the frequency.

That equals = (3 × 10^8) ÷ ( 4.6 × 10^14) = 0.000000652174 m = 652.174 ÷ 10^-9m = 652.174nm

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Answer: Boyle's Law

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Boyle's Law is the pressure-volume law and it relates pressure and volume at constant temperature. Boyle's law states that pressure and volume vary inversely, meaning that as one goes up, the other one goes down.
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3 years ago
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Convert 123 in scientific notation
dalvyx [7]
✡ Answer: 1.23*10^2 ✡


- - Add a decimal at the end (to the right) and count till you get to the first number.
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- - Now you always want to times it by 10 to the power of how many times you moved it over, in this case, 2

Final answer: 1.23*10^2

✡Hope this helps✡


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3 years ago
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Answer:

Atoms, and chemical make up

Explanation:

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3 years ago
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Determine whether each description applies to electrophilic aromatic substitution or nucleophilic aromatic substitution.
Alborosie

Answer:

a. electrophilic aromatic substitution

b. nucleophilic aromatic substitution

c. nucleophilic aromatic substitution

d. electrophilic aromatic substitution

e. nucleophilic aromatic substitution

f. electrophilic aromatic substitution

Explanation:

Electrophilic aromatic substitution is a type of chemical reaction where a hydrogen atom or a functional group that is attached to the aromatic ring is replaced by an electrophile. Electrophilic aromatic substitutions can be classified into five classes: 1-Halogenation: is the replacement of one or more hydrogen (H) atoms in an organic compound by a halogen such as, for example, bromine (bromination), chlorine (chlorination), etc; 2- Nitration: the replacement of H with a nitrate group (NO2); 3-Sulfonation: the replacement of H with a bisulfite (SO3H); 4-Friedel-CraftsAlkylation: the replacement of H with an alkyl group (R), and 5-Friedel-Crafts Acylation: the replacement of H with an acyl group (RCO). For example, the Benzene undergoes electrophilic substitution to produce a wide range of chemical compounds (chlorobenzene, nitrobenzene, benzene sulfonic acid, etc).

A nucleophilic aromatic substitution is a type of chemical reaction where an electron-rich nucleophile displaces a leaving group (for example, a halide on the aromatic ring). There are six types of nucleophilic substitution mechanisms: 1-the SNAr (addition-elimination) mechanism, whose name is due to the Hughes-Ingold symbol ''SN' and a unimolecular mechanism; 2-the SN1 reaction that produces diazonium salts 3-the benzyne mechanism that produce highly reactive species (including benzyne) derived from the aromatic ring by the replacement of two substituents; 4-the free radical SRN1 mechanism where a substituent on the aromatic ring is displaced by a nucleophile with the formation of intermediary free radical species; 5-the ANRORC (Addition of the Nucleophile, Ring Opening, and Ring Closure) mechanism, involved in reactions of metal amide nucleophiles and substituted pyrimidines; and 6-the Vicarious nucleophilic substitution, where a nucleophile displaces an H atom on the aromatic ring but without leaving groups (such as, for example, halogen substituents).

3 0
3 years ago
What is the total number of electron pairs shared between the two atoms in an O2 molecule?
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The answer is (2) 2 pairs. The oxygen atoms combine to get stable structure. So after the combination, each atom needs to have 8 electrons. So when they share 4 electrons can satisfy this requirement. Then there are 2 pairs shared.
8 0
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