Answer:
molecules C6H12O6 = 2.674 E22 molecules.
Explanation:
from periodic table:
⇒ molecular mass C6H12O6 = ((6)(12.011)) + ((12)(1.008)) + ((6)(15.999))
⇒ Mw C6H12O6 = 180.156 g/mol
⇒ mol C6H12O6 = (8.00 g)(mol/180.156 g) = 0.0444 mol C6H12O6
∴ mol ≡ 6.022 E23 molecules
⇒ molecules C6H12O6 = (0.0444 mol)(6.022 E23 molecules/mol)
⇒ molecules C6H12O6 = 2.674 E22 molecules
Answer:
233 g
Explanation:
Let's consider the following reaction.
CaCO₃ → CaO + CO₂
We can establish the following relations:
- The molar mass of calcium carbonate is 100.09 g/mol.
- The molar ratio of calcium carbonate to carbon dioxide is 1:1.
- The molar mass of carbon dioxide is 44.01 g/mol
The mass of carbon dioxide produced from 530 g of calcium carbonate is:
Answer:
wavelength (λ) = 2.73 E-4 m
frecuency (f) = 1.10 E12 s-1
Explanation:
Stefan-Boltzmann law:
- intensity of the radiation for a black body (W) = σ.(T)∧4
∴ σ = 5.670 E-8 W/m²(K)∧4
∴ T = 298 K
⇒ W = (5.670 E-8 W/m²K∧4)×(298 K)∧4
⇒ W = 447.145 W/m² = 447.145 J/s.m²
assuming an area of 1 m²
⇒ W = 447.145 J/s
Rayleigh-Jeans's law:
∴ Black body radiation at a specific wavelength (Bλ(T)):
⇒ Bλ(T) = ( 2 c.k.T ) / (λ)∧4
∴ c = 3 E8 m/s.....velocity of speed
∴ k = 1.38065 E -23 J/K.........Boltzmann's constant
∴ Bλ(T) = 447.145 J/s.m²
⇒ (λ)∧4 = ((2)(3 E8 m/s)(1.38065 E-23 J/K)(298 K)) / (447.145 J/s)
⇒ λ = (5.521 E-15)∧(1/4)
⇒ λ = 2.73 E-4 m
⇒ f = (3 E8 m/s) / (2.73 E-4 m)
⇒ f = 1.10 E12 s-1
