Calcium carbonate decomposes into calcium oxide and carbon dioxide. If 530 g of calcium carbonate decomposes, how many grams of
1 answer:
Answer:
233 g
Explanation:
Let's consider the following reaction.
CaCO₃ → CaO + CO₂
We can establish the following relations:
- The molar mass of calcium carbonate is 100.09 g/mol.
- The molar ratio of calcium carbonate to carbon dioxide is 1:1.
- The molar mass of carbon dioxide is 44.01 g/mol
The mass of carbon dioxide produced from 530 g of calcium carbonate is:
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Explanation:
Since, the given reaction is as follows.
Hence, rate law of the reaction is as follows.
R =
As it is known that rate of a reaction depends on the initial concentration of products. So here, the rate of reaction will depend on the concentration of NO and . Since, power of the concentrations of each of these is equal to 1. Therefore, order of the reaction is equal to 1 + 1 = 2.
According to the rate law, reactants involved in the rate determining step are NO and . Hence, first step of the mechanism is the rate determining step.
Also, according to the rate of reaction doubling the concentration of NO will double the rate of reaction.
The number of reactants taking part in a single step of the reaction is known as molecularity of the reaction. Therefore, molecularity of the first step of the reaction is 2.
Both the given steps are not termolecular.