Calcium carbonate decomposes into calcium oxide and carbon dioxide. If 530 g of calcium carbonate decomposes, how many grams of
1 answer:
Answer:
233 g
Explanation:
Let's consider the following reaction.
CaCO₃ → CaO + CO₂
We can establish the following relations:
- The molar mass of calcium carbonate is 100.09 g/mol.
- The molar ratio of calcium carbonate to carbon dioxide is 1:1.
- The molar mass of carbon dioxide is 44.01 g/mol
The mass of carbon dioxide produced from 530 g of calcium carbonate is:
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Answer:
Explanation:
Given parameters:
Mass of aluminium oxide = 3.87g
Mass of water = 5.67g
Unknown:
Limiting reactant = ?
Solution:
The limiting reactant is the reactant in short supply in a chemical reaction. We need to first write the chemical equation and convert the masses given to the number of moles.
Using the number of moles, we can ascertain the limiting reactants;
Al₂O₃ + 3H₂O → 2Al(OH)₃
Number of moles;
Number of moles =
molar mass of Al₂O₃ = (2x27) + 3(16) = 102g/mole
number of moles = = 0.04mole
molar mass of H₂O = 2(1) + 16 = 18g/mole
number of moles = = 0.32mole
From the reaction equation;
1 mole of Al₂O₃ reacted with 3 moles of H₂O
0.04 mole of Al₂O₃ will react with 3 x 0.04 mole = 0.12 mole of H₂O
But we were given 0.32 mole of H₂O and this is in excess of amount required.
This shows that Al₂O₃ is the limiting reactant
Your final answer is that you will need 52.9mL of the 8.20 M of LiCl
