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castortr0y [4]
2 years ago
14

Question 4 point

Chemistry
1 answer:
Ronch [10]2 years ago
5 0

Answer:

5393.4gH_2O

Explanation:

Hello there!

In this case, for the described chemical reaction, we can write:

CH_4+2O_2\rightarrow CO_2+2H_2O

Thus, by considering the 1:2 mole ratio of methane to water, and the molar mass of the latter (18.02 g/mol), the following is useful to calculate the mass of water that is produced:

149.65molCH_4*\frac{2molH_2O}{1molCH_4} *\frac{18.02gH_2O}{1molH_2O}

Which is equal to:

5393.4gH_2O

Which is not among the choices.

Regards!

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In the front of the room, there is a bottle that contains a 32.00 g sample of sulfur. This is
Vera_Pavlovna [14]
6.02x10^23 atoms is the answer
8 0
3 years ago
If 3.53 g of CuNO, is dissolved in water to make a 0.330 M solution, what is the volume of the solution in milliliters?
solmaris [256]

Answer:

84.8 mL

Explanation:

From the question given above, the following data were obtained:

Mass of CuNO₃ = 3.53 g

Molarity of CuNO₃ = 0.330 M

Volume of solution =?

Next, we shall determine the number of mole in 3.53 g of CuNO₃. This can be obtained as follow:

Mass of CuNO₃ = 3.53 g

Molar mass of CuNO₃ = 63.5 + 14 + (16×3)

= 63.5 + 14 + 48

= 125.5 g/mol

Mole of CuNO₃ =?

Mole = mass / Molar mass

Mole of CuNO₃ = 3.53 / 125.5

Mole of CuNO₃ = 0.028 moles

Next, we shall determine the volume of the solution. This can be obtained as follow:

Molarity of CuNO₃ = 0.330 M

Mole of CuNO₃ = 0.028 moles

Volume of solution =?

Molarity = mole /Volume

0.330 = 0.028 / Volume

Cross multiply

0.330 × Volume = 0.028

Divide both side by 0.330

Volume = 0.028 / 0.330

Volume = 0.0848 L

Finally, we shall convert 0.0848 L to millilitres (mL). This can be obtained as follow:

1 L = 1000 mL

Therefore,

0.0848 L = 0.0848 L × 1000 mL / 1 L

0.0848 L = 84.8 mL

Therefore, the volume of the solution is 84.8 mL.

8 0
2 years ago
Six moles of an ideal gas are in a cylinder fitted at one end with a movable piston. the initial temperature of the gas is 27.0c
Alla [95]

We have to know final temperature of the gas after it has done 2.40 X 10³ Joule of work.

The final temperature is: 75.11 °C.

The work done at constant pressure, W=nR(T₂-T₁)

n= number of moles of gases=6 (Given), R=Molar gas constant, T₂= Final temperature in Kelvin, T₁= Initial temperature in Kelvin =27°C or 300 K (Given).

W=2.4 × 10³ Joule (Given)

From the expression,

(T₂-T₁)=\frac{W}{nR}

(T₂-T₁)= \frac{2.40 X 10^{3} }{6 X 8.314}

(T₂-T₁)= 48.11

T₂=300+48.11=348.11 K= 75.11 °C

Final temperature is 75.11 °C.


6 0
2 years ago
A 15.75 g piece of iron absorbs 1097 joules of heat energy, and its temperature changes from 25°C to 177°C. Calculate the specif
vekshin1

The answer for the following problem is mentioned below.

Explanation:

Given:

mass of iron (m) = 15.75 grams

heat (q) = 1097 J

initial temperature (t_{1}) = 25°C

final temperature (t_{2}) = 177°C

To find:

specific heat (c)

We know;

 c = q ÷ mΔT

where;

c represents the specific heat

q represents the heat

m represents the mass

t represents the temperature

c = \frac{1097}{15.75 * (177-25)}

c = 0.45 J/kg°C

<u><em>Therefore the specific heat capacity of iron is 0.45 J/kg°C.</em></u>

8 0
3 years ago
How many lone pairs are on the central atom of BrF3?
allochka39001 [22]

Answer:

BrF3 has 2 lone pairs (4 unshared electrons)

Explanation:

8 0
3 years ago
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