Question

Question 4 point

Answer 1

Answer:

$5393.4gH_2O$

Explanation:

Hello there!

In this case, for the described chemical reaction, we can write:

$CH_4+2O_2\rightarrow CO_2+2H_2O$

Thus, by considering the 1:2 mole ratio of methane to water, and the molar mass of the latter (18.02 g/mol), the following is useful to calculate the mass of water that is produced:

$149.65molCH_4*\frac{2molH_2O}{1molCH_4} *\frac{18.02gH_2O}{1molH_2O}$

Which is equal to:

$5393.4gH_2O$

Which is not among the choices.

Regards!