Question 4 point
1 answer:
Answer:
Explanation:
Hello there!
In this case, for the described chemical reaction, we can write:
Thus, by considering the 1:2 mole ratio of methane to water, and the molar mass of the latter (18.02 g/mol), the following is useful to calculate the mass of water that is produced:
Which is equal to:
Which is not among the choices.
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We have to know final temperature of the gas after it has done 2.40 X 10³ Joule of work.
The final temperature is: 75.11 °C.
The work done at constant pressure, W=nR(T₂-T₁)
n= number of moles of gases=6 (Given), R=Molar gas constant, T₂= Final temperature in Kelvin, T₁= Initial temperature in Kelvin =27°C or 300 K (Given).
W=2.4 × 10³ Joule (Given)
From the expression,
(T₂-T₁)=
(T₂-T₁)=
(T₂-T₁)= 48.11
T₂=300+48.11=348.11 K= 75.11 °C
Final temperature is 75.11 °C.
The answer for the following problem is mentioned below.
Explanation:
Given:
mass of iron (m) = 15.75 grams
heat (q) = 1097 J
initial temperature () = 25°C
final temperature () = 177°C
To find:
specific heat (c)
We know;
c = q ÷ mΔT
where;
c represents the specific heat
q represents the heat
m represents the mass
t represents the temperature
c =
c = 0.45 J/kg°C
<u><em>Therefore the specific heat capacity of iron is 0.45 J/kg°C.</em></u>