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qaws [65]
2 years ago
5

In the reaction of silver nitrate with copper metal, metallic silver comes out of solution, and the solution turns blue. This as

a ________ reaction. Group of answer choices combustion
Chemistry
1 answer:
nlexa [21]2 years ago
8 0

In the reaction of silver nitrate with copper metal, metallic silver comes out of solution, and the solution turns blue. This as a <u>single replacement</u> reaction.

<h3>What is single replacement reaction?</h3>

A single replacement reaction, also known as a single displacement reaction, occurs when one element in a molecule is swapped out for another. The starting materials are always pure elements, such as a pure zinc metal or hydrogen gas, plus an aqueous compound.

A + BC → B + AC

When A is more reactive than B or when the product AC is more stable than BC, single replacement reactions happen. A and B could either be two halogens or two metals (with hydrogen included) (C is a cation). C functions as a spectator ion when BC and AC are in aqueous solutions.

For example, 2HCl(aq)+Zn(s)→ZnCl₂(aq)+H₂(g)

Learn more about single replacement reactions here:

brainly.com/question/19068047

#SPJ4

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A gas mixture contains 3.00 atm of H2 and 1.00 atm of O2 in a 1.00 L vessel at 400K. If the mixture burns to form water while th
sleet_krkn [62]

Answer:

p_{H_2O}=2.00atm

Explanation:

Hello!

In this case, according to the following chemical reaction:

2H_2+O_2\rightarrow 2H_2O

It means that we need to compute the moles of hydrogen and oxygen that are reacting, via the ideal gas equation as we know the volume, pressure and temperature:

n_{H_2}=\frac{3.00atm*1.00L}{0.08206\frac{atm*L}{mol*K}*400K}=0.0914molH_2 \\\\n_{O_2}=\frac{1.00atm*1.00L}{0.08206\frac{atm*L}{mol*K}*400K}=0.0305molH_2

Thus, the yielded moles of water are computed by firstly identifying the limiting reactant:

n_{H_2O}^{by\ H_2} = 0.0914molH_2*\frac{2molH_2O}{2molH_2} =0.0914molH_2O\\\\n_{H_2O}^{by\ O_2} = 0.0305molO_2*\frac{2molH_2O}{1molO_2} =0.0609molH_2O

Thus, the fewest moles of water are 0.0609 mol so the limiting reactant is oxygen; in such a way, by using the ideal gas equation once again, we compute the pressure of water:

p_{H_2O}=\frac{0.0609molH_2O*0.08206\frac{atm*L}{mol*K}*400K}{1.00L}\\\\ p_{H_2O}=2.00atm

Best regards!

7 0
3 years ago
Describe the ammonium ion, NH4+, and the sulfate ion, SO42-. What compounds would these ions form with potassium and fluoride io
frozen [14]
<span>Cations mix with anions, so you know NH4+ won't mix with K+ and SO4(2-) won't miix with F-. For the reason that NH4+ and F- together have single charges, they'll mix in a 1:1 ratio, NH4F. There's two charges on SO4(2-), so it'll need two K+ to mix with, K2SO4.</span>
6 0
4 years ago
Read 2 more answers
Which process is an example of a chemical change?
Ivanshal [37]
A metal rail rusting in damp weather.
8 0
3 years ago
Read 2 more answers
Calculate AH for the reaction:<br> 2N2 (g) + 6H20 (g) → 302 (g) + 4NH3(g)
Ratling [72]

Answer:

Explanation:

4NH₃ (g) + 3O₂ (g) ⇒ 2N₂ (g) + 6H₂ O(1)

ΔH_r={\sum}{ \Delta }H_f(\text{product})-{\sum}{ \Delta }H_f(\text{reactant})

ΔH r =(2ΔH f(N 2 )+6ΔH f (H 2 O(l)))−(4ΔH f​ (NH 3 (g))+3ΔH f (O 2 (g)))

ΔH rex =[2×0+6×(−286)]−[4×(−46)+3×0]=−1716+186

ΔH rex =−1532kJ/mol

Thermodynamics is a branch of physical chemistry that studies heat and its effects and interactions. Governed by the four main laws, thermodynamics plays a huge role in physics and chemistry, and is also responsible for the law of conservation of energy, a fundamental rule in science.

7 0
2 years ago
Yeast and other organisms can convert glucose (C6H12O6) to ethanol (CH3CH2OH) by a process called alchoholic fermentation. The n
NISA [10]

Answer:

8.37 grams

Explanation:

The balanced chemical equation is:

C₆H₁₂O₆     ⇒   2 C₂H₅OH (l) + 2 CO₂ (g)

Now we are asked to calculate the mass  of glucose required to produce 2.25 L CO₂ at 1atm and 295 K.

From the ideal gas law we can determine the number of moles that the 2.25 L represent.

From there we will use the stoichiometry of the reaction to determine the moles of glucose which knowing the molar mass can be converted to mass.

PV = nRT    ⇒ n = PV/RT

n= 1 atm x 2.25 L / ( 0.08205 Latm/kmol x 295 K ) =0.093 mol CO₂

Moles glucose required:

0.093 mol CO₂  x  ( 1 mol C₆H₁₂O₆   / 2 mol CO₂ ) =  0.046 mol C₆H₁₂O₆

The molar mass of glucose is 180.16 g/mol, then the mass required is

0.046 mol x 180.16 g/mol = 8.37 g

5 0
3 years ago
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