C₀=8.10M
c₁=5.28M
v₀=1.58 L
v₁-?
n=c₀v₀=c₁v₁
v₁=c₀v₀/c₁
v₁=8.10*1.58/5.28=2.42 L
<span>2C2H6 + 7O2 = 4CO2 + 6H2O
</span>
According to the equation of the reaction of ethane combustion, ethane and carbon dioxide have following stoichiometric ratio:
n(C2H6) : n(CO2) = 1 : 2
n(CO2) = 2 x n(C2H6)
n(CO2) = 2 x 5.2 = 10.4 mole of CO2 is formed
Explanation:
It is known that molarity is the number of moles present in a liter of solution.
Molarity = 
Also, number of moles equal mass divided by molar mass. And, molar mass of calcium is 40.07 g/mol.
No. of moles = 
= 
= 0.025 mol
Therefore, calculate the molarity as follows.
Molarity =
= 
= 0.025 M
Thus, we can conclude that molarity of 
in milk is 0.025 M.
Answer:
False
Explanation:
The octet rule forms the basis for chemical reactions. The octet rule states that; an atom is only stable when it has eight electrons around its outermost shell.
This implies that the driving force behind chemical reaction is the attainment of an octet structure(eight electrons in the outermost shell of each of the bonding atoms).
An atom that has only six electrons in its outermost shell is not yet stable according to the demand of the octet rule. Hence, the statement "chemical reactions happen and compounds form because they're trying to get 6 electrons in their outer orbitals" is false.
The boiling point increase of a solution is a colligative property, which means that it is related with the solvent and the concentration of the solute, as per this formula:
ΔT = i * kb * m
Where, ΔT is the increase in the boiling point, i is the van't Hoof factor (which accounts for the numberof particles that are dissolved), kb is the boiling point and m the molality of the solution.
Gvien the normal boiling point of 100°C for pure water, ΔT = 101.4 °C - 100.0 °C = 1.4 °C.
Kb = 0.512 °C / m
m = 1.2 m
Therefore, i = ΔT / (kb * m) = 1.4°C / (0.512 °C/m * 1.2m) = 2.28
Answer: 2.28
