I would look at the minimum and maximum and see if any other the sets don't abide to it. Let's call the first set 1, second set 2, third set 3, fourth set 4. They all have a minimum of 46 and maximum of 108. The median is 75 and since there's 10 numbers in each set, you would have to find the middle of two numbers. First set: Let's put them in order. 46, 66, 68, 68, 70, 70, 80, 82, 85, 108 The median of that set is 70, not 75. Second Set: Let's put them in order. 46, 66, 68, 68, 72, 78, 80, 80, 85, 108 Right away, I can tell the median of the set is 75. We should still check the other sets. Third set: Let's put them in order. 46, 66, 68, 72, 78, 80, 80, 82, 85, 108 Fourth set: Let's put them in order. 46, 66, 68, 68, 72, 78, 80, 82, 85, 108 So, the fourth and second set both have a median of 75. We need to find their third quartile. On the graph, it is about 82 or 83. Second Set's third quartile: 80 Fourth Set's third quartile: 82 So the box plot represents the last set of numbers.
Given the seven letter words "SYSTEMS", if E is always occurring before M it means E and M will always be together therefore they letter 'EM' will be taken as an entity to five us 6letters i.e SYST(EM)S.
This can then be arranged in 6!ways
6! = 6×5×4×3×2×1 = 720ways
Similarly, if the E somewhere before the M and the three Ss grouped consecutively, this means E and M must always be together as well as the Ss to give (SSS)YT(EM).
This means that the letters in the bracket can be taken as an entity to give a total of 4 entities. This can them be arranged in 4! ways.
