Considering that the addresses of memory locations are specified in hexadecimal.
a) The number of memory locations in a memory address range ( 0000₁₆ to FFFF₁₆ ) = 65536 memory locations
b) The range of hex addresses in a microcomputer with 4096 memory locations is ; 4095
<u>applying the given data </u>:
a) first step : convert FFFF₁₆ to decimal ( note F₁₆ = 15 decimal )
( F * 16^3 ) + ( F * 16^2 ) + ( F * 16^1 ) + ( F * 16^0 )
= ( 15 * 16^3 ) + ( 15 * 16^2 ) + ( 15 * 16^1 ) + ( 15 * 1 )
= 61440 + 3840 + 240 + 15 = 65535
∴ the memory locations from 0000₁₆ to FFFF₁₆ = from 0 to 65535 = 65536 locations
b) The range of hex addresses with a memory location of 4096
= 0000₁₆ to FFFF₁₆ = 0 to 4096
∴ the range = 4095
Hence we can conclude that the memory locations in ( a ) = 65536 while the range of hex addresses with a memory location of 4096 = 4095.
Learn more : brainly.com/question/18993173
Step-by-step explanation:
csc x / (cot x + tan x)
Write in terms of sine and cosine.
(1 / sin x) / [(cos x / sin x) + (sin x / cos x)]
Multiply top and bottom by sin x.
1 / [cos x + (sin²x / cos x)]
Multiply top and bottom by cos x.
cos x / (cos²x + sin²x)
Use Pythagorean identity.
cos x / 1
cos x
Rotate one of them so the right angle is in the same orientation as the other one.
1. AB = DE
2. CB = FE
3. AC = DF
4. Compare the length of two known sides: cb and EF
CB = 3 and EF = 8
8/3 = 2 2/3 scale factor
5. Ab is side de. Multiply the length of ab by the scale factor:
4 x 2 2/3 = 10 2/3
6. FD = sqrt ( 10 2/3^2 + 8^2)
FD = 13 1/3
Answer:
6/5
Step-by-step explanation:
Put 1 where x is and solve.
3·1 -5y = -3
-5y = -6 . . . . . subtract 3
y = 6/5 . . . . . . divide by -5
The value of y is 6/5 when x = 1.
Answer: its A
Step-by-step explanation:i did the test
