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AleksAgata [21]
3 years ago
11

How many 1/2 cup servings are there in 7/8 cup of peanut butter?

Mathematics
2 answers:
Gnom [1K]3 years ago
8 0
I think it’s 3/4 cup
docker41 [41]3 years ago
5 0
3/4 cups
is the answer
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Please help me. I am stuck.
dalvyx [7]
C is greater than or equal to $40 (which means put the > sign with a line under it).
4 0
3 years ago
Carrie started work at 8 a.m. and left at 1:30 p.m. How many hours of work should she record on her time card for the day?
vagabundo [1.1K]
Start:  8 a. m.
Finish:  1 : 30 p.m. = 13 hours 30 minutes
13 h 30 min - 8 h = 5 h 30 min
She should record 5 hours and 30 minutes on her time card for the day.
5 0
4 years ago
Read 2 more answers
Please Help With This!!
fomenos

Answer:

f=4

Step-by-step explanation:

-11f=7(1-2f)+5

-11 f=7-14f+5

14f-11f=12

3f=12

f=4

6 0
3 years ago
Is it possible for a triangle to have sides with the given lengths? Explain. 5 in., 8 in., 15 in.
Nitella [24]
<span>Triangle Inequality Theorem

</span><span>the sum of two side lengths of a triangle is always greater than the third side.
</span>
5+8=13 
your answer = no
4 0
4 years ago
Read 2 more answers
According to the Census Bureau, 3.39 people reside in the typical American household. A sample of 26 households in Arizona retir
Vikki [24]

Answer:

t=\frac{2.73-3.39}{\frac{1.22}{\sqrt{26}}}=-2.758    

df=n-1=26-1=25  

p_v =P(t_{(25)}  

Since the p value is lower than the significance level 0.1 we have enough evidence to reject the null hypothesis, and we can conclude that the true mean is significanlty lower than 3.39 personas at 10% of significance.

Step-by-step explanation:

Data given and notation  

\bar X=2.73 represent the sample mean

s=1.22 represent the sample standard deviation

n=26 sample size  

\mu_o =3.39 represent the value that we want to test

\alpha=0.1 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean is less than 3.39 persons, the system of hypothesis would be:  

Null hypothesis:\mu \geq 3.39  

Alternative hypothesis:\mu < 3.39  

The statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{2.73-3.39}{\frac{1.22}{\sqrt{26}}}=-2.758    

P-value

The degreed of freedom are given by:

df=n-1=26-1=25  

Since is a one sided lower test the p value would be:  

p_v =P(t_{(25)}  

Conclusion  

Since the p value is lower than the significance level 0.1 we have enough evidence to reject the null hypothesis, and we can conclude that the true mean is significanlty lower than 3.39 personas at 10% of significance.

3 0
3 years ago
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