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3 years ago

a marathon is 26.2 miles. If Sally ran a marathon in 3 hours 3 minutes what was her approximate pace in minutes?

Mathematics

2 answers:

Tom [10]3 years ago

7 0

Let's turn 3 hours and 3 minutes into minutes.

One hour=60×3=180+3=183

So, there's 183 minutes in 3 hours and 3 minutes. We need to divide 26.2 miles by 183.

26.2÷183≈ 0.143

So, Sally ran 0.143 miles every minute.

Radda [10]3 years ago

3 0

Answer:

0.143 miles/minute

Step-by-step explanation:

Given that a marathon is 26.2 miles. Sally ran a marathon in 3 hours 3 minutes.

Time Sally ran = 3 hours 3 minutes

=3(60+3 = 183 minutes

DIstance travelled = 26.2 miles

Speed per minute = distance/time taken

= $\frac{26.2}{183} \\=0.143$

0.143 miles/minute

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notsponge [240]

Based on the given data; the table represent an inverse variation and the equation that model the data in the table is y = 8/x

<h3>Variation</h3>

Direct variation

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y = k/x

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Learn more about variation:

brainly.com/question/6499629

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2 years ago

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shtirl [24]

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6 0

2 years ago

Read 2 more answers

1.What is the ratio of v to v max expressed as a percentage when [s] = 30 km

Helga [31]

Answer:

(a)96.77%

(b)3.23%

Step-by-step explanation:

Starting with the Michaelis-Menten equation which is used to model biochemical reactions:

Dividing both sides by $V_{\max }}$

$\dfrac{v}{V_{max}}=\dfrac{[S]}{K_M + [S]}$

Where: $V_{\max }} =$ maximum rate achieved by the system

$K_{\mathrm {M} }}$ =The Michaelis constant

${\displaystyle {\ce {[S]}}}=$ Substrate concentration

(a) When $[S]=30K_M$

$\dfrac{v}{V_{max}}=\dfrac{[S]}{K_M + [S]}\\\dfrac{v}{V_{max}}=\dfrac{30K_M}{K_M + 30K_M}\\\dfrac{v}{V_{max}}=\dfrac{30}{1 + 30}\\\dfrac{v}{V_{max}}=\dfrac{30}{31}\\$Expressed as a percentage\\\dfrac{v}{V_{max}}=\dfrac{30}{31}X100=96.77\%$

(b)When $K_M=30[S]$

$\dfrac{v}{V_{max}}=\dfrac{[S]}{K_M + [S]}\\\dfrac{v}{V_{max}}=\dfrac{[S]}{30[S] + [S]}\\\\=\dfrac{1[S]}{30[S] + 1[S]}\\=\dfrac{1}{30 + 1}\\\dfrac{v}{V_{max}}=\dfrac{1}{31}\\$Expressed as a percentage\\\dfrac{v}{V_{max}}=\dfrac{1}{31}X100=3.23\%$