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Vika [28.1K]
3 years ago
5

Solve the system of equations.

Mathematics
1 answer:
aleksandr82 [10.1K]3 years ago
6 0
I did this but got a different answer to it , but most likely it’ll be A , Hope this helps !
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Which rule will find the nth term of the arithmetic sequence<br> -58,-65, -72. -86,...?
Olenka [21]

Answer:

-85n - 7  = -92

Step-by-step explanation:

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3 years ago
All of the students in Ms. Osbourne's class like pizza. Jeff is a student who likes pizza. Therefore, Jeff is a student in Ms. O
faust18 [17]
Whats the question. I need the question to answer.
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The midpoint of JK is M(4, 5). One endpoint is J(5,2). Find the coordinates of the other endpoint K.
Bogdan [553]

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9

Step-by-step explanation:

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7 0
3 years ago
Factor the binomial 9t to second power,-4 =
Naily [24]

Using subtraction of perfect squares, it is found that the factored expression is:

9t² - 4 = (3t - 2)(3t + 2).

<h3>What is the subtraction of perfect squares factoring?</h3>

It is given as follows:

a^2 - b^2 = (a - b)(a + b)

In this problem, the binomial is given as follows:

9t² - 4.

Hence:

  • a² = 9t² -> a = 3t.
  • b² = 4 -> b = 2.

Hence the factored expression is:

9t² - 4 = (3t - 2)(3t + 2).

More can be learned about subtraction of perfect squares at brainly.com/question/16948935

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3 0
2 years ago
Use the order pairs to write a function rule. Give the tule in slope-intercept form.
topjm [15]

to get the equation of any straight line, we simply need two points off of it, so hmmm let's use say (-1 , -1.25) and (8 , -3.5)

(\stackrel{x_1}{-1}~,~\stackrel{y_1}{-1.25})\qquad (\stackrel{x_2}{8}~,~\stackrel{y_2}{-3.5}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-3.5}-\stackrel{y1}{(-1.25)}}}{\underset{run} {\underset{x_2}{8}-\underset{x_1}{(-1)}}}\implies \cfrac{-3.5+1.25}{8+1}\implies \cfrac{-2.25}{9}\implies -\cfrac{~~ \frac{225}{100}~~}{\frac{9}{1}} \\\\\\ -\cfrac{225}{100}\cdot \cfrac{1}{9}\implies -\cfrac{9}{4}\cdot \cfrac{1}{9}\implies -\cfrac{1}{4}

\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-1.25)}=\stackrel{m}{-\cfrac{1}{4}}(x-\stackrel{x_1}{(-1)}) \\\\\\ y+1.25=-\cfrac{1}{4}(x+1)\implies y+\cfrac{5}{4}=-\cfrac{1}{4}x-\cfrac{1}{4} \\\\\\ y=-\cfrac{1}{4}x-\cfrac{1}{4}-\cfrac{5}{4}\implies y=-\cfrac{1}{4}x-\cfrac{6}{4}\implies y=-\cfrac{1}{4}x-\cfrac{3}{2}

3 0
2 years ago
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