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strojnjashka [21]
3 years ago
5

Describe the location of the following coordinates

Mathematics
1 answer:
ser-zykov [4K]3 years ago
8 0
Negative abscissa, zero ordinate is between Quadrant II and Quadrant III.

Hope this helps! :)
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6= x+2/3. what’s the answer :p
djverab [1.8K]

Answer: x = 5 1/3

Step-by-step explanation:

subtract 2/3 from each side

x = 5 1/3

3 0
3 years ago
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There are 203 apples in a basket. How many children can share these apples equally? How many apples would each child get?
tangare [24]
I think this is factorials
so an example would b....... 1*2*3*4*5.... ect

hope this helps
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What are the prime numbers​
AysviL [449]
Prime numbers are only divisible by 1 or itself; the first few are are 2, 3, 5, 7, and 11.
5 0
3 years ago
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A neighborhood trash pick up comes every 5 days, while the recycling pick up is every 8 days. After how many days will both tras
Ivanshal [37]

Answer:

40 days

Step-by-step explanation:

8 and 5 have forty in common so yea forty days

8 0
3 years ago
Based on historical data, your manager believes that 26% of the company's orders come from first-time customers. A random sample
scoundrel [369]

Answer:

\hat p \sim N( p, \sqrt{\frac{p (1-p)}{n}})

And we can use the z score formula given by:

z = \frac{\hat p -\mu_p}{\sigma_p}

And if we find the parameters we got:

\mu_p = 0.26

\sigma_p = \sqrt{\frac{0.26(1-0.26)}{158}} = 0.0349

And we can find the z score for the value of 0.4 and we got:

z = \frac{0.4-0.26}{0.0349}= 4.0119

And we can find this probability:

P(z>4.0119) = 1-P(z

And if we use the normal standard table or excel we got:

P(z>4.0119) = 1-P(z

Step-by-step explanation:

For this case we have the following info given:

p = 0.26 represent the proportion of the company's orders come from first-time customers

n=158 represent the sample size

And we want to find the following probability:

p(\hat p >0.4)

And we can use the normal approximation since we have the following two conditions:

1) np = 158*0.26 = 41.08>10

2) n(1-p) = 158*(1-0.26) = 116.92>10

And for this case the distribution for the sample proportion is given by:

\hat p \sim N( p, \sqrt{\frac{p (1-p)}{n}})

And we can use the z score formula given by:

z = \frac{\hat p -\mu_p}{\sigma_p}

And if we find the parameters we got:

\mu_p = 0.26

\sigma_p = \sqrt{\frac{0.26(1-0.26)}{158}} = 0.0349

And we can find the z score for the value of 0.4 and we got:

z = \frac{0.4-0.26}{0.0349}= 4.0119

And we can find this probability:

P(z>4.0119) = 1-P(z

And if we use the normal standard table or excel we got:

P(z>4.0119) = 1-P(z

8 0
3 years ago
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