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Alexxandr [17]
3 years ago
10

I need help please with this math problem

Mathematics
1 answer:
Arada [10]3 years ago
8 0
When the dilation is centered on the origin, you can multiply each of the individual coordinates by the scale factor.

All the coordinates are ±5 and the scale factor is 1/5. Multiplying those gives ±1. The only selection with all coordinates being ±1 is
.. Selection A.

You can check to see if the signs agree in detail. (They do.)
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How to write 9,009,009 in word form
DaniilM [7]
Nine million nine thousand and nine
7 0
3 years ago
Read 2 more answers
IN NEED OF MORE HELP AND THANK YOU IF YOU ANSWER
Lorico [155]

Answer:

512

Step-by-step explanation:

5.12 converted to a fraction is 512/100

3 0
2 years ago
A community bird-watching society makes and sells simple bird feeders to raise money for its conservation activities. The materi
valentina_108 [34]

Answer:

N(x) = 40 - 2x

P(x) = -2x² + 52 x - 240

maximum profit = 13

Step-by-step explanation:

given data

feeder cost = $6

average sell = 20 per week

price = $10 each

solution

we consider here price per feeder = x

and profit per feeder  id here formula   = x - 6

so that here

total profit will be

P (x)  = ( x - 6 ) Nx

here N(x) is number of feeders sold at price =  x

so formula for N (x)  is here

N(x) = 20 - 2 ( x - 10 )    

N(x) = 40 - 2x

so that

P(x) = (x-6) ( 40 - 2x)

P(x) = -2x² + 52 x - 240

since here

a = -2

b = 52

c = -240

a < 0

so quadratic function have maximum value of c - \frac{b^2}{4a}

so it will be

maximum value = -240 - \frac{52^2}{4(-2)}

maximum value = 98

so here maximum profit attained at

x = \frac{-b}{2a}

x = \frac{-52}{2(-2)}

x = 13

maximum profit = 13

3 0
3 years ago
A statistics textbook chapter contains 60 exercises, 6 of which are essay questions. A student is assigned 10 problems. (a) What
Scilla [17]

Answer:

a) P=0.3174

b) P=0.4232

c) P=0.2594

d) The shape of the hypergeometric, in this case, is like a binomial with mean np=1.

Step-by-step explanation:

The appropiate distribution to model this is the hypergeometric distribution:

P(X=x)=\frac{\binom{s}{x}\binom{N-s}{M-x}}{\binom{N}{M}}=\frac{\binom{6}{x}\binom{54}{10-x}}{\binom{60}{10}}

a) What is the probability that none of the questions are essay?

P(X=0)=\frac{\binom{6}{0}\binom{54}{10-0}}{\binom{60}{10}}\\\\P(X=0)=\frac{1*(54!/(10!*44!)}{60!/(10!*50!)} =\frac{2.3931*10^{10}}{7.5394*10^{10}} = 0.3174

b)  What is the probability that at least one is essay?

P(X=1)=\frac{\binom{6}{1}\binom{54}{9}}{\binom{60}{10}}\\\\P(X=1)=\frac{6*(54!/(9!*43!)}{60!/(10!*50!)} =\frac{3.1908*10^{10}}{7.5394*10^{10}} =0.4232

c) What is the probability that two or more are essay?

P(X\geq2)=1-(P(0)+P(1))=1-(0.3174+0.4232)=1-0.7406=0.2594

8 0
3 years ago
Which graph shows the solution set for 2 x + 3 greater-than negative 9?
sp2606 [1]

I''m pretty sure it's A

6 0
3 years ago
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