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3 years ago

Which is the completely factored form of 4x2+28x+49?

Mathematics

2 answers:

zhenek [66]3 years ago

8 0

Answer: The required factored form of the given expression is $(2x+7)(2x+7).$

Step-by-step explanation: We are given to completely factor the following quadratic expression :

$E=4x^2+28x+49~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

We will be using the following factorization formula :

$(a+b)^2=a^2+2ab+b^2.$

From (i), we have

$E\\\\=4x^2+28x+49\\\\=(2x)^2+2\times x\times7+7^2\\\\=(2x+7)^2\\\\=(2x+7)(2x+7).$

Thus, the required factored form of the given expression is $(2x+7)(2x+7).$

ratelena [41]3 years ago

5 0

(2x+7)(2x+7) hope this helps

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Answer:

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Step-by-step explanation:

The easiest way to solve this is to think of it rephrased as "what is the probability that your second point will be in the same row or column as your first point". With that frame of reference, you can simply consider how many other points are left that do or do not fall in line with the selected one.

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kap26 [50]

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babymother [125]

You're given

x + y + z = 165

7x = n

n = y - 9

n = 9 + z

and you want to find xyz.

Solve the last three equations for x, y, and z :

7x = n → x = n/7

n = y - 9 → y = n + 9

n = 9 + z → z = n - 9

Substitute x, y, and z into the first equation and solve for n :

n/7 + (n + 9) + (n - 9) = 165

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n + 14n = 1155

15n = 1155

n = 77

Now solve for x, y, and z :

x = 77/7 = 11

y = 77 + 9 = 86

z = 77 - 9 = 68

Then the product is

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