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Complete Question
The life of a semiconductor laser at a constant power is normally distributed with a mean of 7,000 hours and a standard deviation of 600 hours. If three lasers are used in a product and they are assumed to fail independently, the probability that all three are still operating after 7,000 hours is closest to? Assuming percentile = 95%
Answer:
0.125
Step-by-step explanation:
Assuming for 95%
z score for 95th percentile = 1.645
We find the Probability using z table.
P(z = 1.645) = P( x ≤ 7000)
= P(x<Z) = 0.95
After 7000 hours = P > 7000
= 1 - P(x < 7000)
= 1 - 0.95
= 0.05
If three lasers are used in a product and they are assumed to fail independently, the probability that all three are still operating after 7,000 hours is calculated as:
(P > 7000)³
(0.05)³ = 0.125
Answer:
5n
Step-by-step explanation:
:)
Answer: Here.
The Solid formed by the net will be a rectangular pyramid.
There are TWO sets of opposite congruent triangular faces.
The base has an area of 30m2
Step-by-step explanation: Don't listen to the B and C dude.
All you do is 1x+2x+5x=8x then you turn 4 s into pints. 1 gallon equals 4 pints 4*4=16 pints. 8x=16 x=2. Then you multiply everything by 2
1*2=2
2*2=4
2*5=10
2pints of soda water
4 pints of fruit punch
10 pints of ginger ale
C . 250 cm^2
cause its the same
