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3 years ago

What is the term for the breakdown of glucose in the absence of oxygen?

Chemistry

1 answer:

Tatiana [17]3 years ago

3 0

Answer:

The breakdown of glucose in the absence of oxygen is termed as anaerobic respiration.

Explanation:

Anaerobic respiration or anaerobic oxidation occur in absence of oxygen molecule within the cytoplasm of cell that ultimately leads to the formation of lactate from pyruvate by the catalytic activity of lactate dehydrogenase enzyme.This reaction helps in the regeneration of NAD+.

During Anaerobic respiration only 2 molecules of ATP are formed by substrate level phosphorylation .

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How many moles are in NaOH?

CaHeK987 [17]

1 mole consist of 6.022 ×10 ²³

Therefore in NaOH = 6.022 ×10 ²³ moles of NaOH

6 0

3 years ago

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What type of chest tube system does this statement describe?

Komok [63]

Answer:

Dry suction chest tube system

Explanation:

The dry suction drains that are self-regulating today use a small, adjustable regulator installed into the drain. 

So long as there is enough air flow from the suction of the wall (that will be shown on the drain) it will respond correctly to changes in the pressure of the source or the patient to retain suction at the drain level.

It's also a quiet mode of activity.

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3 years ago

In the laboratory a student combines 26.2 mL of a 0.234 M chromium(III) acetate solution with 10.7 mL of a 0.461 M chromium(III)

Natalka [10]

Answer: The molarity of $Cr^{3+}$ ions in the solution is 0.299 M

Explanation:

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}$ .....(1)

For chromium (III) acetate:

Molarity of chromium (III) acetate solution = 0.234 M

Volume of solution = 26.2 mL

Putting values in equation 1, we get:

$0.234=\frac{\text{Moles of chromium (III) acetate}\times 1000}{26.2}\\\\\text{Moles of chromium (III) acetate}=\frac{0.234\times 26.2}{1000}=0.00613mol$

1 mole of chromium (III) acetate $(Cr(CH_3COO)_3)$ produces 1 mole of chromium $(Cr^{3+})$ ions and 3 moles of acetate $(CH_3COO^-)$ ions

Moles of $Cr^{3+}\text{ ions}=(1\times 0.00613)=0.00613moles$

For chromium (III) nitrate:

Molarity of chromium (III) nitrate solution = 0.461 M

Volume of solution = 10.7 mL

Putting values in equation 1, we get:

$0.461=\frac{\text{Moles of chromium (III) nitrate}\times 1000}{10.7}\\\\\text{Moles of chromium (III) nitrate}=\frac{0.461\times 10.7}{1000}=0.00493mol$

1 mole of chromium (III) nitrate $(Cr(NO_3)_3)$ produces 1 mole of chromium $(Cr^{3+})$ ions and 3 moles of nitrate $(NO_3^-)$ ions

Moles of $Cr^{3+}\text{ ions}=(1\times 0.00493)=0.00493moles$

For chromium cation:

Total moles of chromium cations = [0.00613 + 0.00493] = 0.01106 moles

Total volume of solution = [26.2 + 10.7] = 36.9 mL

Putting values in equation 1, we get:

$\text{Molarity of }Cr^{3+}\text{ cations}=\frac{0.01106\times 1000}{36.9}\\\\\text{Molarity of }Cr^{3+}\text{ cations}=0.299M/tex]Hence, the molarity of [tex]Cr^{3+}$ ions in the solution is 0.299 M

5 0

3 years ago

What is the name for a metal solution?

bekas [8.4K]

I think it's an Alkaline Solution

7 0

3 years ago

An object exerts 140 N of force on a surface that has an area of 2.0 m2. How much pressure does the object exert?

stepan [7]

The answer will be 70 pascal as pressure =.F upon area

3 0

3 years ago

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