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3 years ago

What is the term for the breakdown of glucose in the absence of oxygen?

Chemistry

1 answer:

Tatiana [17]3 years ago

3 0

Answer:

The breakdown of glucose in the absence of oxygen is termed as anaerobic respiration.

Explanation:

Anaerobic respiration or anaerobic oxidation occur in absence of oxygen molecule within the cytoplasm of cell that ultimately leads to the formation of lactate from pyruvate by the catalytic activity of lactate dehydrogenase enzyme.This reaction helps in the regeneration of NAD+.

During Anaerobic respiration only 2 molecules of ATP are formed by substrate level phosphorylation .

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4.80 x 10^25 formula units pf calcium iodide (Cal2) will have what mass?

maw [93]

Answer:

mass CaI2 = 23.424 Kg

Explanation:

From the periodic table we obtain for CaI2:

⇒ molecular mass CaI2: 40.078 + ((2)(126.90)) = 293.878 g/mol

∴ mol CaI2 = (4.80 E25 units )×(mol/6.022 E23 units) = 79.708 mol CaI2

⇒ mass CaI2 = (79.708 mol CaI2)×(293.878 g/mol) = 23424.43 g

⇒ mass CaI2 = 23.424 Kg

7 0

3 years ago

Number 7 plz tysm guys

morpeh [17]

It is letter C: Continental crust is thicker than oceanic crust.

6 0

3 years ago

Read 2 more answers

How many nitrogen atoms are represented in 2Ca(NO3)2?

arsen [322]

Explanation:

there is 2 nitrogen but if you mean nitrate is 6

4 0

3 years ago

10) an object has mass of 50g 500mg and 0.1g. express the total mass of the object in grams

Pavel [41]

500 mg in g :

1 g ----------- 1000 mg
? -------------- 500 mg

500 x 1 / 1000 => 0.5 g

total mass:

50 g + 0.5 g + 0.1 g => 50.6 g

hope this helps!

8 0

3 years ago

You observe 2 waves named alpha and beta. The alpha wave has a frequency of 5 Hz and the beta wave has a frequency of 2 Hz. Base

MAVERICK [17]

Answer:

shorter wavelength = alpha wave

Explanation:

Given that,

The alpha wave has a frequency of 5 Hz and the beta wave has a frequency of 2 Hz.

We need to compare the wavelengths of these two waves.

For alpha wave,

$\lambda_1=\dfrac{c}{f_1}\\\\\lambda_1=\dfrac{3\times 10^8}{5}\\\\=6\times 10^7\ m$

For beta wave,

$\lambda_2=\dfrac{c}{f_2}\\\\\lambda_2=\dfrac{3\times 10^8}{2}\\\\=15\times 10^7\ m$

From the above calculations, we find that the wavelength of the alpha wave is shorter than the wavelength of the beta wave.

8 0

3 years ago