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goldenfox [79]
2 years ago
13

The chemical formula of calcium oxide is Cao. What is the valency of calcium?

Chemistry
2 answers:
alexandr402 [8]2 years ago
8 0

Answer:

2

Explanation:

In calcium oxide, the calcium is electropositive in nature and to fulfil its octet, the calcium atoms lose two electrons to form the calcium cations whose valency is 2, hence the corresponding anion, i.e. the oxide anion must also have valency 2 to balance the positive charge on the calcium cation.

Hope this helps... 0_0

kykrilka [37]2 years ago
7 0

Lets look out the Electronic configuration of Calcium(Ca)

  • Z=20

EC:-

\\ \rm\longmapsto 1s^22s^22p^63s^2

  • Valency is 2
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Following laboratory safety protocols such as wearing personal protective equipment will protect John when the accident occurred.

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Ad libitum [116K]

1. should be A

Explanation:

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Studentka2010 [4]

Answer:

The answers are in the explanation.

Explanation:

The energy required to convert 10g of ice at -10°C to water vapor at 120°C is obtained per stages as follows:

Increasing temperature of ice from -10°C - 0°C:

Q = S*ΔT*m

Q is energy, S specific heat of ice = 2.06J/g°C, ΔT is change in temperature = 0°C - -10°C = 10°C and m is mass of ice = 10g

Q = 2.06J/g°C*10°C*10g

Q = 206J

Change from solid to liquid:

The heat of fusion of water is 333.55J/g. That means 1g of ice requires 333.55J to be converted in liquid. 10g requires:

Q = 333.55J/g*10g

Q = 3335.5J

Increasing temperature of liquid water from 0°C - 100°C:

Q = S*ΔT*m

Q is energy, S specific heat of ice = 4.18J/g°C, ΔT is change in temperature = 100°C - 0°C = 100°C and m is mass of water = 10g

Q = 4.18J/g°C*100°C*10g

Q = 4180J

Change from liquid to gas:

The heat of vaporization of water is 2260J/g. That means 1g of liquid water requires 2260J to be converted in gas. 10g requires:

Q = 2260J/g*10g

Q = 22600J

Increasing temperature of gas water from 100°C - 120°C:

Q = S*ΔT*m

Q is energy, S specific heat of gaseous water = 1.87J/g°C, ΔT is change in temperature = 20°C and m is mass of water = 10g

Q = 1.87J/g°C*20°C*10g

Q = 374J

Total Energy:

206J + 3335.5 J + 4180J + 22600J + 374J =

30695.5J =

30.7kJ

5 0
3 years ago
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