Answer:
0.25 rad to the nearest hundredth radian
Step-by-step explanation:
Here is the complete question
Suppose a projectile is fired from a cannon with velocity vo and angle of elevation (theta). The horizontal distance R(θ) it travels (in feet) is given by the following.
R(θ) = v₀²sin2θ/32
If vo=80ft/s what angel (theta) (in radians) should be used to hit a target on the ground 95 feet in front of the cannon?
Do not round any intermediate computations, and round your answer(s) to the nearest hundredth of a radian.
(θ)= ?rad
Solution
R(θ) = v₀²sin2θ/32
If v₀ = 80 ft/s and R(θ) = 95 ft
θ = [sin⁻¹(32R(θ)/v₀²)]/2
= [sin⁻¹(32 × 95/80²)]/2
= [sin⁻¹(3040/6400)]/2
= [sin⁻¹(0.475)]/2
= 28.36°/2
= 14.18°
Converting 14.18° to radians, we have 14.18° × π/180° = 0.2475 rad
= 0.25 rad to the nearest hundredth radian
Answer:
-8x=19-3
-8x=16
x= 16/-8
x=-2
Step-by-step explanation:
Well, keep in mind that the domain of a function is the entire set of possible values of the independent variable. To make it more clear, the domain is the set of all possible x-values, which will make the function work, and with real y-values as the output. So, the range would be the set of all of the second elements of an ordered pair (y-coordinates).
If you made a T chart like the picture you have above, you would have to put x (age of person) and y (books read).
So,
x = age of person
y = books read
The answer would be -15.74
Rewrite the equation into slope intercept form:
8y = -5x+16
divide everything by 8 to get just y
y = -5/8x+2
the slope = -5/8
