Answer:
The yellow box.
Step-by-step explanation:
According to the graph, 10 students get off the bus every 2 minutes. Do 10 divided by 2 to find out how many students get off the bus each minute. Since the answer is 5, that means 5 students get off the bus each minute.
Answer:
x = -11
Step-by-step explanation:
I'm assuming it's an isosceles triangle so 32 + 2x = 10;
subtract 32 from both sides;
2x = -22
x = -11
The fraction that should be removed is 1/5.
<h3>How to calculate the fraction?</h3>
It should be noted that from the information, 40% of the coins are 20-cent coins and the rest are 50-cent coins. Those that are 50 cent will be:
= 100 - 40%
= 60%
The fraction that's should be removed will be:
= 2/5 - x = 1/5
x = 2/5 - 1/5
x = 1/5
The fraction that should be removed is 1/5.
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Answer: 0.2643
Step-by-step explanation:
Given : The proportion of adults are unemployed : p=0.077
The sample size = 300
By suing normal approximation to the binomial , we have


Now, using formula
, the z-value corresponding to 26 will be :-

Using standard distribution table for z , we have
P-value=

Hence, the probability that at least 26 in the sample are unemployed =0.2643