Let numbers of books be 'b' and numbers of CDs be 'c'
We can set up two equations:
Equation [1] ⇒

Equation [2] ⇒

We are solving for the number of books and the number of CDs bought
When we have two equations in terms of two different variables;

and

, that we need to solve, then this becomes a simultaneous equation problem.
First, rearrange Equation [1] to make either

or

the subject:


Then we substitute

into Equation [2]






Now we know the value of

which is

, substitute this value into

we have

Answer:
Numbers of books = 13
Numbers of CDs = 7
Since there are six numbers, on average 1,2,or 3 will come up 50 percent of the time and 4,5, and 6 will also come up 50 percent
The least common denominator is: 60
Then comparing 100/60 with 100/60
<span>100/60 = 100/60,
therefore,
20/12 = 25/15</span>
Answer:
C.
Step-by-step explanation:
-6 4/5 and 64/5 are opposites or a zero pair so when you add them you get zero.