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8_murik_8 [283]
3 years ago
9

Find the equation of the line that passes through the following two points: (3, -7) and (7, 2)

Mathematics
1 answer:
Wittaler [7]3 years ago
6 0

Answer:

y=\frac{9}{4}x-\frac{55}{4}

Step-by-step explanation:

Slope-intercept form: y = mx + b

Slope formula: \frac{y2-y1}{x2-x1}

Given points: (3, -7), (7, 2)

(3, -7) = (x1, y1)

(7, 2) = (x2, y2)

To write the equation in slope-intercept form, we need to find the slope(m) and the y-intercept(b) of the equation.

First, let's find the slope. To do this, input the given points into the slope formula:

\frac{2-(-7)}{7-3}

Simplify:

2 - (-7) = 2 + 7 = 9

7 - 3 = 4

\frac{9}{4}

The slope is \frac{9}{4}.

To find the y-intercept, input the slope and one of the given points(in this example I'll use point (7, 2)) into the equation and solve for b:

2=\frac{9}{4}(7)+b

2=\frac{63}{4}+b

-\frac{55}{4} =b

The y-intercept is -\frac{55}{4}.

Now that we know the slope and the y-intercept, we can write the equation:

y=\frac{9}{4}x-\frac{55}{4}

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