Hybrid = having one recessive and one dominant allele
This means that all of the flowers must have the genotype Bb.
Knowing this, let's make a Punnet Square.

As you can see, 3 of these are going to have the dominant trait and 1 is going to have the recessive trait. This corresponds to our 3:1 in our question, meaning that the black seeds must be dominant and the brown ones recessive.
Because they are dominant, the genotype for black seeds could be
BB <em /><em>or</em>
Bb.
Answer:
for the first question the answer is cell. And the second questiob the answer is energy
They become more large and are less able to divide and multiply.Which as an increase in pigment and a fatty substance inside the cell . (Hopes this helped)
Answer:
The correct answer is c. 3/16.
Explanation:
In the given question two traits being studied, the traits are flower color and seed shape.
This is a typical Mendel’s dihybrid cross. According to the question purple colour (P) and round seed (R) are dominant traits.
When heterozygous purple-flowered (Pp), round-seeded (Rr) individuals are crossed, four different types of plants are produced phenotypically in the ratio 9:3:3:1.Out of 16 offspring, 9 are purple flowered, round seeded pea plants, 3 pea plants are white-flower with round seed, 3 are purple- flower with wrinkled seed and 1 pea plant is white-flowered with wrinkled seed pea plant is produced.
Explanation:
They differ when they have the same chemical composition but the way in which they are arranged or put together is different.