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rewona [7]
3 years ago
12

What are the solutions to the equation Sqrt5x + 1 = x + 1?

Mathematics
1 answer:
DerKrebs [107]3 years ago
8 0

Answer: x=6.7016                 I hope this will help

Step-by-step explanation: STEP 1.

Isolate the square root on the left hand side

    Radical already isolated

    √5x-1 = x-1  

STEP 2.

Eliminate the radical on the left hand side

    Raise both sides to the second power

    (√5x-1)2 = (x-1)2

    After squaring

    5x-1 = x2-2x+1STEP

Step 3.

Solve the quadratic equation

    Rearranged equation

    x2  - 7x  + 2 = 0

    This equation has two real roots:

      x1 = ( 7 + sqrt( 41) ) / 2 = 6.7016

     x2 = ( 7 - sqrt( 41) ) / 2 = 0.2984STEP

Step 4.

Check that the first solution is correct

    Original equation

    √5x-1 = x-1

    Plug in 6.7016 for  x

     √5•( 6.7016) -1 = ( 6.7016) -1

     Simplify

     √32.508 = 5.702

     Solution checks !!

    Solution is:

     x =  6.7016 STEP

Step 5.

Check that the second solution is correct

    Original equation

    √5x-1 = x-1

    Plug in 0.2984 for  x

     √5•( 0.2984) -1 = ( 0.2984) -1

     Simplify

     √0.492 = -0.702

     Solution does not check

     0.702 ≠ -0.702

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