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Mademuasel [1]
3 years ago
5

The coping method that involves changing the way you feel or emotionally react to a stressor is known as _________.

Physics
1 answer:
expeople1 [14]3 years ago
6 0
The appropriate response is Emotion-centered coping. It is a particular system that was produced in the 1980s by the clinicians Susan Folkman and Richard Lazarus, and these methods concentrate on changing one's passionate response to an unpleasant or disquieting circumstance, for example, getting a finding of a terminal disease.
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That process is called the Miranda rights
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Identify the labeled parts in the figure.
ad-work [718]

Answer:

Chemical symbols Al, O, H, O or a,c,f,h.

Coefficient 2  or e.

Number of atoms of the element - b,d ,g.

One atom of the element - i.

5 0
3 years ago
Impact of electricity in the society
Travka [436]

Answer:

<h2>Electricity has many uses in our day to day life. It is used for lighting rooms, working fans and domestic appliances like using electric stoves, A/C and more. All these provide comfort to people. In factories, large machines are worked with the help of electricity.</h2>

5 0
2 years ago
A coil 3.95 cm radius, containing 520 turns, is placed in a uniform magnetic field that varies with time according to B=( 1.20×1
Pie

Answer:

(a) E= 3.36×10−2 V +( 3.30×10−4 V/s3 )t3

(b) I=0.0085\ A

Explanation:

Given:

  • radius if the coil, r=0.0395\ m
  • no. of turns in the coil, n=520
  • variation of the magnetic field in the coil, B=(1.2\times 10^{-2})t+(3.45\times 10^{-5})t^4
  • resistor connected to the coil, R=560\ \Omega

(a)

we know, according to Faraday's Law:

emf=n.\frac{d\phi}{dt}

where:

d \phi= change in associated magnetic flux

\phi= B.A

where:

A= area enclosed by the coil

Here

A=\pi.r^2

A=\pi\times 0.0395^2

A=0.0049\ m^2

\therefore \phi=((1.2\times 10^{-2})t+(3.45\times 10^{-5})t^4)\times 0.0049

So, emf:

emf= 520\times \frac{d}{dt} [((1.2\times 10^{-2})t+(3.45\times 10^{-5})t^4)\times 0.0049]

emf= 520\times 0.0049\times \frac{d}{dt} [(1.2\times 10^{-2})t+(3.45\times 10^{-5})t^4)]

emf= 2.548\times [0.012+(13.8\times 10^{-5})t^3)]

emf= 0.0306+3.516\times 10^{-4}\ t^3

(b)

Given:

t_0=5.25\ s

Now, emf at given time:

emf=4.7755\times 10^{-2}\ V

∴Current

I=\frac{emf}{R}

I=\frac{4.7755\times 10^{-2}}{560}

I=8.5\times 10^{-5} A

6 0
4 years ago
How do you divide 5 km by 2 hours?
aleksandr82 [10.1K]

                    5 km  /  2 hrs

               =   (5/2)  (km/hr)

               =      2.5 km/hr .  
7 0
3 years ago
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