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3 years ago

The coping method that involves changing the way you feel or emotionally react to a stressor is known as _________.

1 answer:

6 0

The appropriate response is Emotion-centered coping. It is a particular system that was produced in the 1980s by the clinicians Susan Folkman and Richard Lazarus, and these methods concentrate on changing one's passionate response to an unpleasant or disquieting circumstance, for example, getting a finding of a terminal disease.

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A person travels from New York to Washington at the rate of 45 km per hour and

mr_godi [17]

Answer:

The average speed for the whole journey is 49.5 miles per hour.

Explanation:

Step 1 :

Here, both the ways, he covers the same distance. Then, the formula to find average speed is

= 2xy / (x+y)

Step 2 :

x ----> Rate at which he travels from New York to Washington

x = 45

y ----> Rate at which he travels from New York to Washington

y = 55

Step 3 :

So, the average speed is

= (2 ⋅ 45 ⋅ 55) / (45 + 55)

= 4950 / 100

= 49.5

8 0

3 years ago

A 5.30kg block hangs from a spring with a spring constant 1700 N/m. The block is pulled down 4.50cm from the equilibrium positio

Andru [333]

To solve this problem it is necessary to apply the concepts related to the frequency in a spring, the conservation of energy and the total mechanical energy in the body (kinetic or potential as the case may be)

PART A) By definition the frequency in a spring is given by the equation

$f = \frac{1}{2\pi} \sqrt{\frac{k}{m}}$

Where,

m = mass

k = spring constant

Our values are,

k=1700N/m

m=5.3 kg

Replacing,

$f = \frac{1}{2\pi} \sqrt{\frac{1700}{5.3}}$

$f=2.85 Hz$

PART B) To solve this section it is necessary to apply the concepts related to the conservation of energy both potential (simple harmonic) and kinetic in the spring.

$\frac{1}{2}kA^2 = \frac{1}{2}mv^2 + \frac{1}{2} kY^2$

Where,

k = Spring constant

m = mass

y = Vertical compression

v = Velocity

This expression is equivalent to,

$kA^2 =mV^2 +ky^2$

Our values are given as,

k=1700 N/m

V=1.70 m/s

y=0.045m

m=5.3 kg

Replacing we have,

$1700*A^2=5.3*1.7^2 +1700*(0.045)^2$

Solving for A,

$A^2 = \frac{5.3*1.7^2 +1700*(0.045)^2}{1700}$

$A ^2 = 0.011035$

$A=0.105 m \approx 10.5 cm$

PART C) Finally, the total mechanical energy is given by the equation

$E = \frac{1}{2}kA^2$

$E=\frac{1}{2}1700*(0.105)^2$

$E= 9.3712 J$

3 0

3 years ago

Two cubes, one silver and one iron, have the same mass and temperature. A quantity Q of heat is removed from each cube. Which on

scoundrel [369]

Answer:

C) specific heat capacity

Explanation:

As we know that heat given to the system to change the temperature is given as

$Q = ms \Delta T$

here we know that

Q = thermal energy given to the system

s = specific heat capacity of the system

$\Delta T$ = change in temperature

so here we know that

$\Delta T = \frac{Q}{ms}$

here we know that heat given to the two cubes is of same amount as well as the mass is same but the final temperature is different because of the specific heat capacity (s)

So correct answer would be

C) specific heat capacity

8 0

3 years ago

As the temperature of a liquid increases, the solubility of a solid in the liquid

nexus9112 [7]

D, it depends. For water, the solubility increases as it get hotter, up to 100 degrees, but in some cases, liquids behave the opposite way.

4 0

2 years ago

Which model correctly represents the product or products of the chemical reaction?

fgiga [73]

Answer:

you can go to quizlet in really helps.

Explanation:

7 0

2 years ago