Question

A hand-crank generator inputs 160 Joules of energy into a light bulb over the course of 2.5 seconds. Calculate the power

Answer 1

The power being dissipated by the hand-crank generator is 94.12 Watts.

Given the following data:

• Energy = 160 Joules.

• Power = 2.5 seconds.

To find the power being dissipated by the hand-crank generator:

Mathematically, power is given by the formula;

$Power = \frac{Energy}{Time}$

Substituting the given parameters into the formula, we have;

$Power = \frac{160}{1.70}$

Power = 94.12 Watts.

Therefore, the power being dissipated by the hand-crank generator is 94.12 Watts.

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