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2 years ago

A hand-crank generator inputs 160 Joules of energy into a light bulb over the course of 2.5 seconds. Calculate the power

Physics

1 answer:

Reptile [31]2 years ago

4 0

The power being dissipated by the hand-crank generator is 94.12 Watts.

Given the following data:

Energy = 160 Joules.

Power = 2.5 seconds.

To find the power being dissipated by the hand-crank generator:

Mathematically, power is given by the formula;

$Power = \frac{Energy}{Time}$

Substituting the given parameters into the formula, we have;

$Power = \frac{160}{1.70}$

Power = 94.12 Watts.

Therefore, the power being dissipated by the hand-crank generator is 94.12 Watts.

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3 years ago

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Answer:

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The vertical velocity of the motorcycle at time t is given by (free-fall motion):

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where

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Answer:

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Marat540 [252]

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