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ivolga24 [154]
3 years ago
13

A hand-crank generator inputs 160 Joules of energy into a light bulb over the course of 2.5 seconds. Calculate the power

Physics
1 answer:
Reptile [31]3 years ago
4 0

The power being dissipated by the hand-crank generator is 94.12 Watts.

<u>Given the following data:</u>

  • Energy = 160 Joules.
  • Power = 2.5 seconds.

To find the power being dissipated by the hand-crank generator:

Mathematically, power is given by the formula;

Power = \frac{Energy}{Time}

Substituting the given parameters into the formula, we have;

Power = \frac{160}{1.70}

Power = 94.12 Watts.

Therefore, the power being dissipated by the hand-crank generator is 94.12 Watts.

Read more: brainly.com/question/12193740

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I attached the picture of the missing table.
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Part 1
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I will do all the calculations in the google sheet that I will share with you.
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Part 3
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Part 4
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Part 5
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Here is the link to the spreadsheet:
https://docs.google.com/spreadsheets/d/1SkQHbI1BxiJnwpWbLmP0XWgcNPrGquH1K2MfN6cznVo/edit?usp=sharing

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