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dezoksy [38]
3 years ago
8

The total pressure for a fluid is a. the sum of the hydrostatic and static pressures. b. the sum of the hydrostatic and dynamic

pressures. c. the sum of the static and dynamic pressures. d. the sum of the static, dynamic, and hydrostatic pressures.
Physics
1 answer:
m_a_m_a [10]3 years ago
3 0

<h2>The option a is most appropriate </h2>

Explanation:

The total pressure due to liquid column at any place is the sum of

( i ) pressure due to liquid column called hydrostatic pressure

( ii ) the pressure due to air column above the liquid column , which is called the static pressure

Thus total pressure is the sum of hydrostatic and static pressure .

Thus the option a is most appropriate

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Answer:

256.25 A

Explanation:

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A ray of light traveling in air is incident on the surface of a block of clear ice (of index 1.309) at an angle of 25.5 ◦ with t
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Answer: 135.29\º

The figure attached will be helpful to understand the solution.

Here we see two cases, reflection and refraction of light.

According to the laws of reflection:

1. The incident ray, the reflected ray and the normal are in the same plane.

2. The angle of incidence is equal to the angle of reflection.

<u>*Note the normal is perpendicular to the plane, with a 90\º angle with the surface</u>

And this can be visualized in the figure, where the angle {\theta}_{1} with which the incident ray hits the surface is equal to the angle with which this same ray is reflected.

On the other hand we have Refraction, a phenomenon in which  the light bends or changes its direction when passing through a medium with a refractive index different from the other medium.

In this context, the Refractive index is a number that describes how fast light propagates through a medium or material.  

According to Snell’s Law:  

n_{1}sin(\theta_{1})=n_{2}sin(\theta_{2})     (1)  

Where:  

n_{1}=1 is the first medium refractive index  (the air)

n_{2}=1.309 is the second medium refractive index  (the ice)

\theta_{1}=25.5\º is the angle of the incident ray  

\theta_{2} is the angle of the refracted ray  

Now, firstly we have to find \theta_{2} and then, by geometry, find \alpha and \beta which sum the <u>angle between the reflected and the refracted light</u>.

Finding \theta_{2} from (1):

(1)sin(25.5\º)=(1.309)sin(\theta_{2})    

sin(\theta_{2})=0.328

\theta_{2}=arcsin(0.328)

\theta_{2}=19.201\º   (2)

Remembering that the Normal makes  a 90\º angle with the surface, we can say:

90\º=\theta_{1}+\beta    (3)

Finding \beta:

\beta=90\º-25.5\º=64.5\º    (4)

Doing the same with  \theta_{2} and  \alpha}:

90\º=\theta_{2}+\alpha    (5)

Finding \alpha:

\alpha=90\º-19.201\º=70.79\º    (6)

Adding both angles (4) and (6):

\alpha+\beta=70.79\º+64.5\º    (7)

\alpha+\beta=135.29\º>>>This is the angle between the reflected and the refracted light.

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If do 50 J of Work in 20 seconds, what is my Power ?
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A point charge Q is located a distance d away from the center of a very long charged wire. The wire has length L &gt;&gt; d and
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Answer:

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now the force on the other charge in this electric field is given as

F = QE

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