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Luba_88 [7]
3 years ago
10

Imagine that you could throw a baseball at a speed of 29,000 km/h. What would happen to the ball if you threw it that fast?

Physics
1 answer:
lorasvet [3.4K]3 years ago
7 0

Answer:

If you threw a baseball at the speed of light, the ball would move 299,792,458 kilometers per second. Unlike light, a baseball has mass as it approaches the speed of light, its mass would increase towards infinity. As nothing can go faster than the speed of light, it is known as the speed limit of the universe.

Explanation:

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A railroad car of mass M moving at a speed v1 collides and couples with two coupled railroad cars, each of the same mass M and m
marshall27 [118]

Answer:

vf = v₁/3 + 2v₂/3

Explanation:

Using the law of conservation of linear momentum,

momentum before impact = momentum after impact

So, Mv₁ + 2Mv₂ = 3Mv (since the railroad cars combine) where v₁ = initial velocity of first railroad car, v₂ = initial velocity of the other two coupled railroad cars, and vf = final velocity of the three railroad cars after impact.

Mv₁ + 2Mv₂ = 3Mvf

dividing through by 3M, we have

v₁/3 + 2v₂/3 = vf

vf = v₁/3 + 2v₂/3

6 0
3 years ago
One form of energy can be _____ another type of energy.
kotegsom [21]

We can answer this one very quickly.  From the <em>Law of Conservation of Energy</em>, we know that "Energy can't be created or destroyed.".

So that only leaves us one way to complete the sentence in this question:

"One form of energy can be <em>transformed into</em> another type of energy. "  <em>(B)</em>

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3 years ago
Thirty five soccer players were challenged to do as many sit-ups possible in two minutes
Ghella [55]

Answer:

Explanation:

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7 0
3 years ago
The spin quantum number is represented by the symbol ______ and has the possible values ______, corresponding to the two directi
yanalaym [24]

The spin quantum number is represented by the symbol m s a nd has the possible values  +1/2.-1/  corresponding to the two directions of the electron's magnetic field.

The magnetic quantum quantity tells us what number of orbitals there are in a subshell and the feasible orientations of those orbitals. Its value is dependent on the angular momentum quantum range.

The  magnetic discipline is an area in area close to a magnet or an electric contemporary wherein a physical area is produced from a shifting electric rate that creates force on some other shifting electric rate. An instance of a magnetic field is the Earth's magnetic

All magnets have north and south poles. contrary poles are drawn to every other, whilst the identical poles repel each different. when you rub a chunk of iron alongside a magnet, the north-in search of poles of the atoms in the iron line up inside the identical route. The force generated by using the aligned atoms creates a magnetic subject.

Learn more about quantum numbers here:-brainly.com/question/25786066

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6 0
2 years ago
A point charge of +3 C is located at the origin of a coordinate system and a second point charge of -6 C is at x = 1.0 m. At w
Butoxors [25]

Answer:

The point at which the electrical potential is zero is x = +0.33 m.

Explanation:

By definition the electrical potential is:

V_{E} = \frac{K*q}{r}

Where:

K: is Coulomb's constant = 9x10⁹ N*m²/C²

q: is the charge

r: is the distance

The point at which the electrical potential is zero can be calculated as follows:

V_{1} + V_{2} = 0

K(\frac{q_{1}}{r_{1}} + \frac{q_{2}}{r_{2}}) = 0    (1)

q₁ is the first charge = +3 mC

r₁ is the distance from the point to the first charge  

q₂ is the first charge = -6 mC

r₂ is the distance from the point to the second charge    

By replacing r₁ = 1 - r₂ into equation (1) we have:

K(\frac{q_{1}}{1 - r_{2}} + \frac{q_{2}}{r_{2}}) = 0   (2)

By solving equation (2) for r₂:

r_{2} = \frac{q_{1}}{q_{1} - q_{2}} = \frac{3 mC}{3 mC - (-6 mC)} = +0.33 m

                 

Therefore, the point at which the electrical potential is zero is x = +0.33 m.

I hope it helps you!  

8 0
3 years ago
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