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Luba_88 [7]
3 years ago
10

Imagine that you could throw a baseball at a speed of 29,000 km/h. What would happen to the ball if you threw it that fast?

Physics
1 answer:
lorasvet [3.4K]3 years ago
7 0

Answer:

If you threw a baseball at the speed of light, the ball would move 299,792,458 kilometers per second. Unlike light, a baseball has mass as it approaches the speed of light, its mass would increase towards infinity. As nothing can go faster than the speed of light, it is known as the speed limit of the universe.

Explanation:

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A child has an ear canal that is 1.3 cm long. At what sound frequencies in the audible range will the child have increased heari
ElenaW [278]

Answer:

The answer to this is

6600 Hz to 19,800 Hz

Explanation:

The shape of the human ear is analogous to a closed ended pipe hence

we have λ = 4L or wavelength = 4 * length of the child ear

The frequency  c/λ  where c = speed of sound = 343 m/s

hence the child's audible range is multiples of 343/(4*0.13) =6600Hz

or 13200 Hz or 19,800 Hz

The generally quoted range of human hearing is 20 Hz to 20 kHz

7 0
3 years ago
What is Humpty Dumpty's momentum if he has a mass of 56kg and is walking to the wall at a rate of 3 m/s? ​
Sophie [7]

Answer:

168

Explanation:

56 x 3

have a nice day

5 0
3 years ago
According to the law of conservation of matter, the number of ________ is not changed by a chemical reaction.
kondaur [170]
The answer should be atoms.
3 0
3 years ago
Read 2 more answers
Describe the conditions necessary for equilibrium on a balance.
tia_tia [17]

Answer:

Explanation:

A body under concurrent forces (concurrent forces are forces with their line of action acting at a point) is said to be in equilibrium if the sum total of the forces acting on the body is zero.

For forces acting on a balance, the sum of upward forces and the downward forced acting on the balance must be equal for the balance to be in equilibrium.

Also the sum of clockwise moment must be equal to the sum of anticlockwise moment acting on the balance.

Moment is the product of force and the perpendicular distance from the force to the pivot.

7 0
4 years ago
g HW 5.6.The Moon and the Earth both orbit the center of mass of the Earth-Moon system.Earth is 81 times more massive than the M
Law Incorporation [45]

Answer:

R_{cm}  = 4.688 106 m

Explanation:

The expression for the center of mass is

       R cm = 1 / M ∑ r_{i} m_{i}

Where M is the total mass of the system, ri and m1 are the distance and mass of each particle from a defined origin

Let's look for the total mass, the mass of the moon is m and that of the earth Me

    M = M_{e} + m

    M = 81m + m

    M = 82 m

The distance from the earth to the moon is R = 384.4 106 m

    R_{cm} = 1 / M (M R1 + m R)

   R_{cm}  = 1 / 82m (0 + m R)

    R_{cm}  = R / 82

   R_{cm}  = 384.4 106/82

   R_{cm}  = 4.688 106 m

The radius of the earth is

    R_{e} = 6371 103 m

    R_{e}  = 6.371 106 m

We can see that the center of mass of the system is within the beating radius

6 0
3 years ago
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