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4 years ago

A 12-volt car battery uses about 660 amps. How much power does it use?

2 answers:

8 0

We know, Power = Voltage * Current
P = 660 * 12 = 7920 watt

In short, Your Answer would be Option A

Hope this helps!

Diano4ka-milaya [45]4 years ago

6 0

Answer:

7,920

Explanation:

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Given that the electromagnetic force is far stronger than gravity on a per-particle basis, why doesn't the electromagnetic force

Kaylis [27]

Explanation:

The electro magnetic force is given by

F = $\frac{k.q_{1}.q_{2}}{r^{2}}$

where $q_{1}$ and $q_{2}$ are charged particles

k =Coulombs constant

r = distance between two charges

And gravitational force is given by

F = $\frac{G.m_{1}.m_{2}}{r^{2}}$

where $m_{1}$ and $m_{2}$ are masses

G =Garvitation constant

r = distance between two masses

Now since the planets, stars and galaxies are electrically neutral, therefore they have zero electrical charge and so electro magnetic forces have no affect on these planets, stars and heavenly bodies.

Whereas the masses of the heavenly bodies are very large, so they are largely affected by the gravitational force since Gravitational force is directly proportional to the product of the masses of a body.

Therefore, though the electromagnetic force is stronger than the gravitational force, the electromagnetic force does not dominate the forces in the heavenly bodies as they as not electrically charged.

8 0

4 years ago

In a charming 19th-century hotel, an old-style elevator is connected to a counterweight by a cable that passes over a rotating d

melisa1 [442]

Answer:

2.38732 rpm

1.22625 rad/s²

163.292°

Explanation:

g = Acceleration due to gravity = 9.81 m/s²

a = Acceleration = $\frac{1}{8}g$

d = Diameter of wheel = 2 m

r = Radius of wheel = $\frac{d}{2}=\frac{2}{2}=1\ m$

v = Speed of elevator = 25 cm/s

Angular speed is given by

$\omega=\frac{v}{r}\\\Rightarrow \omega=\frac{0.25}{1}\\\Rightarrow \omega=0.25\ rad/s=0.25\times \frac{60}{2\pi}\\\Rightarrow \omega=2.38732\ rpm$

The angular speed of the wheel is 2.38732 rpm

Angular acceleration is given by

$\alpha=\frac{a}{r}\\\Rightarrow \alpha=\frac{\frac{1}{8}g}{r}\\\Rightarrow \alpha=\frac{\frac{1}{8}\times 9.81}{1}\\\Rightarrow \alpha=1.22625\ rad/s^2$

The angular acceleration of the wheel is 1.22625 rad/s²

Angular displacement is given by

$\theta=\frac{s}{r}\\\Rightarrow \theta=\frac{2.85}{1}\\\Rightarrow \theta=2.85\ rad=2.85\times \frac{360}{2\pi}\\ =163.292\ ^{\circ}$

The angle the disk turned when it has raised the elevator is 163.292°

4 0

3 years ago

The spectrum from a hydrogen vapour lamp is measured and four lines in the visible light range are observed. These lines are the

Elan Coil [88]

Answer:

$10942249.24 m^{-1}$

Explanation:

Rydberg's formula is used to describe the wavelengths of the spectral lines of chemical elements similar to hydrogen, that is, with only one electron being affected by the effective nuclear charge. In this formula we can find the rydberg constant, knowing the wavelength emitted in the transcision between two energy states, we can have a value of the constant.

$\frac{1}{\lambda}=Z^2R(\frac{1}{n^2_{1}}-\frac{1}{n^_{2}^2}})$

Where $\lambda$ it is the wavelength of the light emitted, R is the Rydberg constant, Z is the atomic number of the element and $n_{1} n_{2}$ are the states where $n_{1}$ .

In this case we have Z=1 for hydrogen, solving for R:

$R=\frac{1}{\lambda}*(\frac{1}{n^2_{1}}-\frac{1}{n^_{2}^2}})^{-1}\\R=\frac{1}{658.9*10^{-9}m}*(\frac{1}{2^2}-\frac{1}{3^2}})^{-1}\\R=1.52*10^6m^{-1}*(\frac{36}{5})=1.09*10^7 m^{-1}=10942249.24m^{-1}$