21. A 60 kg student on a scooter is pushed with a constant force of 40 N across a horizontal concrete driveway at a constant spe
1 answer:
The magnitude of the force of friction is 40 N
Explanation:
To solve the problem, we just have to analyze the forces acting on the student and the scooter along the horizontal direction. We have:
- The constant pushing force forward, of magnitude F = 40 N
- The frictional force, acting backward,
Since the two forces are in opposite direction, the equation of motion is
where
m is the mass of the student+scooter
a is the acceleration
However, here the scooter is moving at constant speed: this means that its acceleration is zero, so
a = 0
And therefore,
which means that the magnitude of the force of friction is also equal to 40 N.
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Answer: The correct answer is (C).
Explanation:
Supply function:
Demand function:
S(p)=D(p), price for which supply is equal to demand:
After solving this above equation graphically, we will get the values of p.
1) p =96.236
2) p=( -118.258)
We will reject the negative value of p.
So, the value of p that price for which the supply equals the demand is $ 96.236 $96.24. Hence, the correct answer is option (C).
