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jonny [76]
3 years ago
7

Solve for x d(-3+x)=kx+9

Mathematics
2 answers:
vekshin13 years ago
7 0

x=3(3+d)/ d-k

Hope this helps:)

ANEK [815]3 years ago
6 0

Answer:

x = \frac{9+3d}{d-k}

Step-by-step explanation:

Given

d(- 3 + x) = kx + 9 ← distribute parenthesis on left side

- 3d + dx = kx + 9 ( add 3d to both sides )

dx = kx + 9 + 3d ( subtract kx from both sides )

dx - kx = 9 + 3d ← factor out x from each term on the left side

x(d - k) = 9 + 3d ← divide both sides by (d - k)

x = \frac{9+3d}{d-k}

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How are the graphs of the functions f(x) = √16^x and g(x) =3√64^x related?
liberstina [14]

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Explanation:-

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(a^n)^m=a^{nm}

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3 years ago
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<u>Our problem:</u>

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