relative max = pi -2
relative min = -2 pi
Step-by-step explanation:
y= 4x- 2tan(x), (-pi/2,pi/2)
To find relative max and min,
According to mathematical procedure to find relative max and relative min,
the following procedure should be carry out.
Derivating equation with respect to x,
.....(1)
Equating equation (1) to Zero,
We get,
....stationary point
There are total three points
1. -pi/2 2. pi/2 3. pi/4
checking local min and local max
first considering -pi/2;
...(2)
putting x= pi/4 in equation (2),
we get,
<0
So, we have local max at x=pi/4
by putting value of x in equation (1);
we get,
.... is maximum point.
Similarly, at x= -pi/ 2,
>0
So, we have local min at x=-pi/2
by putting value of x in equation (1);
we get,
.... is minimum point