Answer:
<u>The area of the larger triangle is 315 inches²</u>
Step-by-step explanation:
1. Let's review all the information provided for answering the questions properly:
Pre-image triangle has a base of 7 inches and a height of 10 inches
Scale used : Factor of 3
2. What is the area of the larger triangle??
For calculating the area of the larger triangle, we use the scale this way:
Base = 7 inches * 3
21 inches
Height = 10 inches * 3
30 inches
Area of the larger triangle = 1/2 (Base * Height)
Area of the larger triangle = 1/2 (21 * 30)
<u>Area of the larger triangle = 630/2 = 315 inches²</u>
Answer:
A ≈ 269.81 cm²
Step-by-step explanation:
This shape is a hexagon (it has 6 sides) so let's use the formula for the area of a hexagon.
A = 
Where s is the length of the sides
Substitute:
A =
A = 
Solve:
A =
A = 
Multiply the numerator:
A =
A ≈ 
(The numerator reflects a rounded number, but the actual calculations are exact)
Divide the fraction:
A ≈
A ≈ 2.6(100)
Multiply:
A ≈ 2.6(100)
A ≈ 269.81 cm²
Therefore, the area is approximately 269.82 cubic centimeters.
<h3>
Answers:</h3><h3>
6 quarters</h3><h3>
2 dimes</h3>
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Work Shown:
d = number of dimes
q = number of quarters
q = d+4 since she has 4 more quarters than dimes
$1.70 = 170 cents
10d = value of all the dimes in cents
25q = value of all the quarters in cents
10d+25q = total value of all the coins in cents
10d+25q = 170
10d+25( q ) = 170
10d+25( d+4 ) = 170 .... plug in q = d+4
10d+25d+100 = 170 .... distribute
35d+100 = 170
35d = 170-100 ..... subtract 100 from both sides
35d = 70
d = 70/35 ... divide both sides by 35
d = 2
He has 2 dimes
q = d+4
q = 2+4
q = 6
He also has 6 quarters
------------------
Check:
1 dime = 10 cents
2 dimes = 20 cents ..... multiply both sides by 2
1 quarter = 25 cents
6 quarters = 150 cents ..... multiply both sides by 6
(2 dimes) + (6 quarters) = (20 cents) + (150 cents) = 170 cents
This confirms the answers.
Answer:
Step-by-step explanation:
The equations given are:
For the equations to generate the same independent value, then
This implies that:
Group similar terms to get:
Simplify to get:
