The width used for the car spaces are taken as a multiples of the width of
the compact car spaces.
Correct response:
- The store owners are incorrect
<h3 /><h3>Methods used to obtain the above response</h3>
Let <em>x</em><em> </em>represent the width of the cars parked compact, and let a·x represent the width of cars parked in full size spaces.
We have;
Initial space occupied = 10·x + 12·(a·x) = x·(10 + 12·a)
New space design = 16·x + 9×(a·x) = x·(16 + 9·a)
When the dimensions of the initial and new arrangement are equal, we have;
10 + 12·a = 16 + 9·a
12·a - 9·a = 16 - 10 = 6
3·a = 6
a = 6 ÷ 3 = 2
a = 2
Whereby the factor <em>a</em> < 2, such that the width of the full size space is less than twice the width of the compact spaces, by testing, we have;
10 + 12·a < 16 + 9·a
Which gives;
x·(10 + 12·a) < x·(16 + 9·a)
Therefore;
The initial total car park space is less than the space required for 16
compact spaces and 9 full size spaces, therefore; the store owners are
incorrect.
Learn more about writing expressions here:
brainly.com/question/551090
Step-by-step explanation:
EF = 6x - 4
and it is also the combination of EG and GF.
so,
6x - 4 = EG + GF = EG + 13
6x = EG + 17
now, we have additional information. EF bisects CD. that means it cuts CD in half.
and that means both banks must be off equal size.
5x - 1 = 7x -13
12 = 2x
x = 6
so, back to the first problem
6×6 = EG + 17
36 = EG + 17
19 = EG
<span><u><em>The correct answer is: </em></u>
129,407.
<u><em>Explanation</em></u><span><u><em>: </em></u>
12 ten-thousands = 12*10000=120,000.
8 thousands = 8*1000=8000;
<u>this gives us</u> 120,000+8,000=128,000.
14 hundreds = 14*100=1400;
<u>this gives us</u> 128,000+1,400=129,400.
7 ones = 7*1=7;
<u>this gives us</u> 129,400+7=129,407.</span></span>
Answer:
The Perimeter is 4.5in and the Area is 1.125in²
Step-by-step explanation:
Perimeter is gotten by adding up the length/height of every side of the polygon (1.5in + 1.5in + 0.75in + 0.75in), while the Area of a rectangle is gotten by multiplying the height and length. (1.5in × 0.75in)
U have to divide the numbers with the variables and then you'll get knocked down to the division and u have your answers and it is possible to have 1 or 2 answers v
