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Virty [35]
4 years ago
7

Explain what causes STIs and how they are transmitted

Physics
1 answer:
aliya0001 [1]4 years ago
7 0
Hey, Terrizzif!
STIs are caused by sexual transmission, they are spread by sexual intercourse.
I hope this helps;)
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2. While hiking, you see a fragment of rock drop vertically from the edge of a cliff to the ground below. Which of the following
Dafna11 [192]

Answer:

Your answer would be B. fall

Explanation:

This is because sliding would be continuous it just said a fragment of rock fell vertically. Hope this helps

  • {/} OfficialQue09 {/}
8 0
3 years ago
Read 2 more answers
What kind of small objects composes much of the universe?
Inga [223]
It’s atoms thank me later (give me brailiest)
7 0
3 years ago
For a particular reaction, Δ H ∘ = − 93.8 kJ and Δ S ∘ = − 156.1 J/K. Assuming these values change very little with temperature,
svetoff [14.1K]

To solve this problem it is necessary to apply the concepts related to Gibbs free energy and spontaneity

At constant temperature and pressure, the change in Gibbs free energy is defined as

\Delta G = \Delta H - T\Delta S

Where,

H = Entalpy

T = Temperature

S = Entropy

When the temperature is less than that number it is negative meaning it is a spontaneous reaction. \Delta  G is also always 0 when using single element reactions. In numerical that implies \Delta G = 0

At the equation then,

\Delta G = \Delta H - T\Delta S

0 = \Delta H - T\Delta S

\Delta H = T\Delta S

T = \frac{\Delta H}{\Delta S}

T = \frac{-93.8kJ}{-156.1J/K}

T = \frac{-93.8*10^3J}{-156.1J/K}

T = 600.89K}

Therefore the temperature changes the reaction from non-spontaneous to spontaneous is 600.89K

5 0
3 years ago
The masses of two heavenly bodies are 2×10‘16’ and 4×10 ‘22’ kg respectively and the distance between than is 30000km. find the
ycow [4]

F = 5.93×10^{13}\:\text{N}

Explanation:

Given:

m_1= 2×10^{16}\:\text{kg}

m_2= 4×10^{22}\:\text{kg}

r = 30000\:\text{km} = 3×10^7\:\text{m}

Using Newton's universal law of gravitation, we can write

F = G\dfrac{m_1m_2}{r^2}

\:\:\:\:=(6.674×10^{-11}\:\text{N-m}^2\text{/kg}^2)\dfrac{(2×10^{16}\:\text{kg})(4×10^{22}\:\text{kg})}{(3×10^7\:\text{m})^2}

\:\:\:\:= 5.93×10^{13}\:\text{N}

3 0
3 years ago
What is the force that acts on an object and opposes its motion called?
Alika [10]
Friction is the force that acts on an object and opposes its motion
5 0
3 years ago
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