On August 10, 1972, a large meteorite skipped across the atmosphere above the western United States and western Canada, much lik
e a stone skipped across water. The accompanying fireball was so bright that it could be seen in the daytime sky and was brighter than the usual meteorite trail. The meteorite's mass was about 4.0 × 106 kg; it's speed was about 13 km/s. Had it entered the atmosphere vertically, it would have hit Earth's surface with about the same speed. (a) Calculate the meteorite's loss of energy (as a positive number, in joules) that would have been associated with the vertical impact. (b) Express the energy as a multiple of the explosive energy of 1 megaton of TNT, which is 4.2 × 1015 J. (c) The energy associated with the atomic bomb explosion over Hiroshima was equivalent to 13 kilotons of TNT. To how many Hiroshima bombs would the meteorite impact have been equivalent?
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Given:
mass = 6 kg
velocity = 4 m/s
To find:
Kinetic energy of the cart = ?
Formula used:
Kinetic energy =
Where m = mass of the cart
v = velocity with which the cart is moving
Solution:
Kinetic energy of the moving cart is given by,
Kinetic energy =
Where m = mass of the cart
v = velocity with which the cart is moving
Kinetic energy =
Kinetic energy = 48 Joule
Thus, the kinetic energy of the moving cart is 48 Joule.
- Initial velocity=u=15m/s
- Final velocity=v=10m/s
- Time=0.08s