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Maksim231197 [3]
3 years ago
14

Let this oscillator have the same energy as a mass on a spring, with the same k and m, released from rest at a displacement of 5

.00cm from equilibrium. what is the quantum number n of the state of the harmonic oscillator? express the quantum number to three significant figures.
Physics
1 answer:
allochka39001 [22]3 years ago
3 0
There are a lot of same examples that you may have worked before, where the mass on a spring uses a classics when it comes to mechanics. So in this system, always put in your mind that there is an enormous quantum standard that one can use in the equation. It should be 2.10x10 raise to a negative sixth. J.
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Answer:

v = 44.27 m / s

Explanation:

This is an exercise in kinematics since they ask the maximum speed of the train

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Answer:

  • Corey's max speed is 7 \frac{m}{s}
  • the distance Corey's covers in z seconds is 7 \frac{m}{s} * z \ s
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  • d (x) = 45 m + 7 \frac{m}{s} * (x-7 s)

Explanation:

<h3>Corey's max speed</h3>

For constant speed, we know:

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v_{max}=\frac{35 m}{5 s} = 7 \frac{m}{s}

<h3>How far runs Corey</h3>

As the velocity of Corey's is v_{max}, the distance Corey's covers in z seconds is

distance = v_{max} * z \ s

distance = 7 \frac{m}{s} * z \ s

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At time 7 + z seconds the distance will be the 45 meters he covers in the first part of the race plus the distance he traveled at constant speed. this is:

d (z) = 45 m + v_{max} * z

d (z) = 45 m +7 \frac{m}{s} * z

At time x ( x greater or equal to 7 seconds) the distance will be the 45 meters he covers in the first part of the race plus the distance he traveled at constant speed. this is:

d (x) = 45 m + v_{max} * (x-7 s)

d (x) = 45 m + 7 \frac{m}{s} * (x-7 s)

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