2. Calcular la masa de un cuerpo, si al recibir una fuerza, cuya magnitud de

Physics

1 answer:

Tom [10]2 years ago

5 0

Answer:

la masa de un cuerpo = 67.308 kg

Explanation:

De la pregunta, sabemos que,

magnitud de fuerza (F) = 350 N = 350 Kg / m / $s^{2}$

Aceleración (a)= 520 cm / $s^{2}$ = 5.20 m / $s^{2}$

A encontrar: la masa de un cuerpo (m)

Nosotras sabemos que, F = m *a

m = $\frac{F}{a}$

= $\frac{350 kg / m / s^{2} }{5.20 m / s^{2} }$

= 67.308 kg

Entonces, la masa de un cuerpo = 67.308 kg

You might be interested in

Page is

Ede4ka [16]

Answer:

72 m

Explanation:

Given:

v₀ = 0 m/s

v = 60 m/s

a = 25 m/s²

Find: Δx

v² = v₀² + 2aΔx

(60 m/s)² = (0 m/s)² + 2 (25 m/s²) Δx

Δx = 72 m

6 0

2 years ago

If the moment acting on the cross section is M=630N⋅m, determine the maximum bending stress in the beam. Express your answer to

-BARSIC- [3]

Answer:

2.17 Mpa

Explanation:

The location of neutral axis from the top will be

$\bar y=\frac {(240\times 25)\times \frac {25}{2}+2\times (20\times 150)\times (25+(\frac {150}{2}))}{(240\times 25)+2\times (20\times 150)}=56.25 mm$

Moment of inertia from neutral axis will be given by $\frac {bd^{3}}{12}+ ay^{2}$

Therefore, moment of inertia will be

$\frac {240\times 25^{3}}{12}+(240\times 25)\times (56.25-25/2)^{2}+2\times [\frac {20\times 150^{3}}{12}+(20\times 150)\times ((25+150/2)-56.25)^{2}]=34.5313\times 10^{6} mm^{4}}$