An airplane touches down on the runway with a speed of 70 m/s2. Determine the airplane after each second of its deceleration.
1 answer:
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<h2>Law 1:</h2><h3>An object already in motion stays in motion, unless acted upon by a force.</h3><h3 /><h2>Law 2:</h2><h3>
</h3><h3>f = forces on an object</h3><h3>m = mass of that object</h3><h3>a = acceleration of that object</h3><h3 /><h2>Law 3:</h2><h3>Everything has an equal and opposite reaction.</h3><h3 /><h3>Hope this helps!</h3>
Answer:
The change in momentum is
Explanation:
From the question we are told that
The mass of the probe is
The location of the prob at time t = 22.9 s is
The momentum at time t = 22.9 s is
The net force on the probe is
Generally the change in momentum is mathematically represented as
The initial time is 22.6 s
The final time is 22.9 s
Substituting values