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2 years ago

An airplane touches down on the runway with a speed of 70 m/s2. Determine the airplane after each second of its deceleration.

1 answer:

ivann1987 [24]2 years ago

5 0

<span>vf^2 = vi^2 + 2*a*d
---
vf = velocity final
vi = velocity initial
a = acceleration
d = distance
---
since the airplane is decelerating to zero, vf = 0
---
0 = 55*55 + 2*(-2.5)*d
d = (-55*55)/(2*(-2.5))
d = 605 meters

</span>

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3 years ago

In each of two coils the rate of change of the magnetic flux in a single loop is the same. The emf induced in coil 1, which has

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3 years ago

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3 years ago

Suppose the coefficient of static friction between the road and the tires on a car is 0.638 and the car has no negative lift. Wh

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When the car is on the verge of sliding we have the force equation

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2 years ago