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2 years ago

If the normal force exerted on an object increases, the coefficient of sliding friction will also increase. True False

Physics

2 answers:

lbvjy [14]2 years ago

4 0

Answer:

FALSE

Explanation:

As we know that the friction force between two sliding surfaces is given by the formula

$F_f = \mu F_n$

here

$\mu$ = coefficient of friction

it depends on the the inter molecular force between the molecules of the two surfaces which slide over each other

now if we will increase the normal force then it will increase the force of friction

but if will not change the value of coefficient of friction between two surface as it is property of the surface only

professor190 [17]2 years ago

3 0

The answer is false

I hope I helped

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An incident ray of light strikes water at an angle of 30°. The index of refraction of air is 1.0003, and the index of refraction

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Answer: It’s A

Explanation:

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2 years ago

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Un vas plin cu lichid cântăreşte 175kg. Ceea ce reprezintă de 5 ori masa vasului gol. Ştiind că volumul interior al vasului este

Mariana [72]

a) Density of the liquid: $823.5kg/m^3$

b) Weight of the liquid: 1372 N

Explanation:

Translation of the text:

"A full tank with liquid weighs 175kg. Which is 5 times the mass of the empty vessel. Knowing that the inside volume of the vessel is 0.17kl, calculate:

a) the density of the liquid;

b) the weight of the liquid."

We know that the full tank with liquid has a total mass of M = 175 kg. We can write the total mass as

$M=m_L + m_V$ (1)

where

$m_L$ is the mass of the liquid

$m_V$ is the mass of the vessel

We also know that the total mass M is 5 times the mass of the empty vessel, so we have:

$M=5m_V\\m_V=\frac{M}{5}=\frac{175}{5}=35 kg$

which is the mass of the empty vessel.

Therefore, we can find the mass of the liquid only using (1):

$m_L=M-m_V=175-35=140 kg$

The density of the liquid is given by

$d=\frac{m}{V}$

where

m = 140 kg (mass of the liquid)

V = 0.170 kL = 170 L = $0.170 m^3$ (volume of the liquid, which is equal to the volume of the vessel)

So we get

$d=\frac{140}{0.170}=823.5kg/m^3$

The weight of a body is given by

$F=mg$

where

m is its mass

g is the acceleration due to gravity

For the liquid in this problem, we have

m = 140 kg (mass)

$g=9.8 m/s^2$ (acceleration due to gravity)

Therefore, its weight is

$F=(140)(9.8)=1372 N$

Learn more about density:

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2 years ago

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barxatty [35]

I think this is the solution:

1: U-1, F,-4
2: Na-6, Mo-1, O-4
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8: H-7, F-1
9: N-1, O-5, H-1, S-1
10: H-8
11: Nb-1, O-1, C-1, I-3
12: C-3, F-3, S-1, O-3, H-1
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2 years ago

How do the tension of the cord and the force of gravity affect a pendulum?

LuckyWell [14K]

Answer:

Force of gravity may not affect a pendulum during its equilibrium state. But the gravity can affect the pendulum when a force occurs in any direction of the bob connected to the cord that makes a swing sideways. The gravity of pendulum never stops, it always accelerates. So the gravity affects the pendulum acceleration and speed.

Similarly the tension in the cord will not affect the pendulum but if change in the length of the pendulum while keeping other factors constant changes the length of the period of pendulum. longer pendulum swings with lower frequency than shorter pendulums.

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2 years ago

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Pls help :(( I need help!! Its physics! motion and forces!

Delvig [45]

Answer: Pedaling your bike : acceleration :: applying the brakes : inertia.

The reason I think this to be the answer to the analogy is because there is energy and work used in both processes (and the unit focuses on forces); gravity is constant and does not change whether one pedals or applies brakes. And I do not think it's deceleration, as deceleration tends to equate to acceleration within the physics perspective.

Edit: I should also add that since you clarified that your unit is motion and forces, Newtons 1st law is the law of inertia. The way to change an objects motion for it to slow down is by applying an additional force. That resistance the bike experiences to slow is the process of inertia. Inertia happens in order to accelerate an object (either by slowing it down, or speeding it up): i.e., the resistance to change.

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