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pshichka [43]
4 years ago
6

How many calls will you need to make to hit your sales target for the month I need to make 23 more sales. My current close ratio

is 1:3.5, so I will need to make?
Physics
1 answer:
Marizza181 [45]4 years ago
7 0
<span>Closing ratio is the number of deals you close compared to the number of presentations ( or calls ) you make. In this case it means: 1 sale : 3.5 calls ( average ). We will use proportions: 1 : 3.5 = 23 : x. x = 23 * 3.5, x = 80.5. We have to round this number upwards to be more certain that you get the 23 sales. Answer: 81 calls </span>
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With e in volts per meter and t in seconds. at t = 0, the field is upward. the plate area is 4. 3 × 10-2 m2. for t &gt; 0, what
kenny6666 [7]

The magnitude of the displacement current between the plates is    2.1*10^{-8} A

Given,

A=4.3*10^{-2}  m^{2}

E=(4.0*10^{5})-(6.0*10^{4}t)\\

i_{d}  =ϵ_{0} *\frac{dϕ_{E} }{dt } =ϵ_{0}A\frac{dE}{dt}

i_{d}=ϵ_{0}*A*\frac{d}{dt}(4.0*10^{5})-(6.0*10^{4}t)=-ϵ_{0} *A*6.0*10^{4}

= -(8.85*10^{-12})(4.0×10*^{-2})(6.0×10^{4})=-2.1*10^{-8} A

<h3>Current </h3>

An electrical charge carrier flow known as current often involves electrons or atoms lacking in electrons. The capital letter I is frequently used as a symbol for current. Amperes are the common unit and are denoted by the letter A. A coulomb of electrical charge moves past a certain place in one second as one ampere of current does. Franklin current or conventional current are terms used by physicists to describe how current flows from relatively positive to comparatively negative sites. Negatively charged electrons are the most prevalent charge carriers. They move in a somewhat good direction from relatively negative points.

With e in volts per meter and t in seconds. at t = 0, the field is upward. the plate area is 4. 3 × 10-2 m2. for t > 0, what is the magnitude of the displacement current between the plates?

Learn more about current here:

brainly.com/question/13076734

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2 years ago
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3 years ago
Two people with a combined mass of 127 kg hop into an old car with worn-out shock absorbers. This causes the springs to compress
Elena-2011 [213]

Answer:

Total load = 2999.126 kg

Explanation:

Let the spring constant of the shock absorber be k.

We know that the force applied on a spring is directly proportional to elongated length and the constant of proportionality is called spring constant.

Thus

Force, F = kx

where,

x = elongation = 9.1 cm 0.091 m

mass of the people, m = 127 kg

F = weight of the people = mg = 127 x 9.8 = 1244.6 N

substituting these values in the first equation,

1244.6 = k x 0.091

thus, k = 13,676.923 N/m

Now we know that the time period, T of an oscillating spring with a load of mass m is

T = 2\pi \sqrt{\frac{m}{k} }

\frac{m}{k} = \frac{T^{2} }{4\pi ^{2} }

thus,

m = k\frac{T^{2} }{4\pi ^{2}}

T = 1.66s

substituting these values in the equation,

m =13,676.923\frac{1.66^{2} }{4\pi ^{2}  }

m = 2999.126 kg

3 0
3 years ago
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