The effective spring constant of the system is 39.6 N/m
Explanation:
The frequency of oscillation of a spring-mass system is given by
where
k is the spring constant of the system
m is the mass
In this problem, we have:
f = 29 Hz is the frequency of vibration of the eyeball system
m = 7.5 g = 0.0075 kg is the mass
We can therefore re-arrange the equation to find the effective spring constant of the system. We find:
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Answer:
0.0238 centimetre
Explanation:
multiply the length value by 100
Answer:
-10 m/s²
Explanation:
a = Δv / Δt
a = (20 m/s − 50 m/s) / 3 s
a = -10 m/s²
Answer:the force will remain same
Explanation:
because force is equal to the ratio of magnitude and distance
