Answer:
data member as an array named stack of size 50 to store certain elements Three member functions i.e. push(type) to add elements in the Stack, pop() to ...
Depends on what you are working on.
If you are working on a website I recommend Adobe Dreamweaver CC.
if its small assignments that doesnt involve major work, I'd use something like notepad++
Answer:
Network Operating System (NOS)
Explanation:
A network operating system (NOS) is an operating system that makes different computer devices connect to a common network in order to communicate and share resources with each other using a server. A network operating system can be used by printers, computers, file sever among others, and they are connected together using a local area network. This local area network which they are connected to works as the server.
The NOS also acts as a network security because it could be used as an access control or even user authentication.
There are two types of NOS
1) Peer to peer network operating system.
2) Client/server network operating system
A network operating system (NOS) is a server-based operating system oriented to computer networking and may include directory services, network management, network monitoring, network policies, user group management, network security, and other network-related functions.
Answer:
public boolean equals(Object other)
{
// check correct instance
if (other instanceof IntTree)
{
try
{
IntTree otherTree = (IntTree) other;
return equals(overallRoot, otherTree.overallRoot);
}
// caught exceptions
catch (Exception e)
{
return false;
}
}
return false;
}
public boolean equals(IntTreeNode tree1, IntTreeNode tree2)
{
// if reach ends
if (tree1 == null && tree2 == null)
{
// they are equal
return true;
}
else if (tree1 == null || tree2 == null)
{
// not equal
return false;
}
// check left part
boolean leftPart = equals(tree1.left, tree2.left);
// check current element is same
boolean currentPart = tree1.element.equals(tree2.element);
// check right part
boolean rightPart = equals(tree1.right, tree2.right);
// all are equal
return (leftPart && currentPart && rightPart);
}
Explanation:
