Question

Use right triangle DCB to find the trig values for angle D. sinD = cosD = tanD =

Answer 1

Sin D=35/37
cos D=12/37
tan D= 35/12
Use SOHCAHTOA

Answer 2

Answer:

$sin(D)=\frac{35}{37}$

$cos(D)=\frac{12}{37}$

$tan(D)=\frac{35}{12}$

Step-by-step explanation:

Part a) Find $sin(D)$

we know that

In a right triangle the value of sine of  an angle is equal to the opposite side to the angle  divided by the hypotenuse

$sin(D)=\frac{CB}{DB}$

substitute the values

$sin(D)=\frac{35}{37}$

Part b) Find $cos(D)$

we know that

In a right triangle the value of cosine of  an angle is equal to the adjacent side to the angle  divided by the hypotenuse

$cos(D)=\frac{DC}{DB}$

substitute the values

$cos(D)=\frac{12}{37}$

Part c) Find $tan(D)$

we know that

In a right triangle the value of tangent of  an angle is equal to the opposite side to the angle  divided by the adjacent side to the angle

$tan(D)=\frac{CB}{DC}$

substitute the values

$tan(D)=\frac{35}{12}$